1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
babymother [125]
3 years ago
11

State why hexadecimal is used to display the error code

Computers and Technology
1 answer:
maxonik [38]3 years ago
7 0
“Hexadecimal uses digits that more closely resemble our usual base-10 counting system and it's therefore easier to decide at a glance how big a number like e7 is as opposed to 11100111. Higher information density. With 2 hexadecimal digits, we can express any number from 0 to 255.”
You might be interested in
Choosing the “Quick Print” button will ____________.
harkovskaia [24]
Choosing the "Quick Print" button will print to the default print (Answer is B). The quick print function is accessible in the Quick Access Tool bar . By clicking the drop down arrow of the quick access tool bar it will let you choose different types of default access including your Quick print.
7 0
4 years ago
The background image does not affect any cell’s format or content. _______
Korvikt [17]
Hmmm...that is true 
Here a quizlet about if you need it!
https://quizlet.com/15207805/csci-241-flash-cards/
3 0
3 years ago
Write a function named dice_eval that accepts two parameters representing numeric dice values and returns a string describing th
Zigmanuir [339]

Following are the "dice_eval" method code into python language.

Program Explanation:

  • Defining a method "dice_eval" that takes two variables "d1,d2" in its parametes.
  • Inside the method, multiple conditional statements were used that adds the parameter values and calculates its value which can be defined as follows:
  • In the if block, it adds the parameters and uses or gate that check its value that is equal to 7 or 11. so, it will return a string message that is 'Winner!'.  
  • In the elif block, it adds the parameters and uses or gate that check its value that is equal to 2 or 3 or 12. so, it will return a string message that is ' C r aps ! '.
  • In the else block, it uses a return keyword that adds parameter value and prints a string value.
  • Outside the method "d1,d2" is declared that inputs the value from the user-end, and passes the value into the method, and prints its value.

Program:

def dice_eval(d1, d2):#defining a method dice_eval that takes two parameters

if (d1+d2)==7 or (d1+d2)==11:#defining if block that adds parameter value and use or operator to check its value

return 'Winner!'#return string value

elif (d1+d2)==2 or (d1+d2)==3 or (d1+d2)==12:#defining elif block that adds parameter value and use or operator to check its value

return 'C r aps!'#return string value

else:#defining else block

return 'Point is '+str(d1+d2)#return string value with adding parameter

d1=int(input())#defining d1 that input value

d2=int(input())#defining d2 that input value

print(dice_eval(d1,d2))#calling method and print its return value

Output:

Please find the attached file

Please find the complete code in the attached file.

Learn more:

brainly.com/question/15011927

4 0
3 years ago
What is the maximum number of elements that will be visited by the binary search algorithm when searching a sorted 45-element ar
sergey [27]

The max nukber of elements visited will be 6.

6 0
2 years ago
Write your code to define and use two functions. The Get User Values function reads in num Values integers from the input and as
ZanzabumX [31]

Answer:

#include <iostream>

#include <vector>

using namespace std;

/* Define your function here */

vector<int> GetUserValues(vector<int>& userValues, int numValues) {

  int tmp = 0;

  vector<int> newVec;

 

  for(int i = 0; i < numValues; i++) {

     cin >> tmp;

     newVec.push_back(tmp);

     

  }

 

  return newVec;

}

void OutputIntsLessThanOrEqualToThreshold(vector<int> userValues, int upperThreshold) {

  for (int i = 0; i < userValues.size(); ++i) {

     if(userValues.at(i) < upperThreshold) {

          cout << userValues.at(i) << " ";

     }

  }

 

  cout << endl;

}

int main() {

  vector<int> userValues;

  int upperThreshold;

  int numValues;

 

  cin >> numValues;

  userValues = GetUserValues(userValues, numValues);

  cin >> upperThreshold;

  OutputIntsLessThanOrEqualToThreshold(userValues, upperThreshold);

  return 0;

}

Explanation:

Perhaps their is a better way to code this, but I couldn't figure out what to do with the pointer in the first function.

6 0
3 years ago
Other questions:
  • To specify grouping and sorting for a report, click the ____ button on the design tab in layout view.
    14·1 answer
  • Write a function M-file that takes as input two matrices A and B, and as output produces
    8·1 answer
  • Explain the concept of risk management, including risk identification, assessment, and control.
    5·1 answer
  • Which of the following reflects Moore's law? Multiple Choice The doubling of computer chip performance per dollar every two year
    11·1 answer
  • Dan works for an automobile company. He has designed a new model of a car based on an older version. Which technology can he use
    6·1 answer
  • A slow response when opening applications or browsing the Internet, applications that do not work properly, an operating system
    5·2 answers
  • Which of the following is true about radio waves? They have short wavelengths. They have high energies. They reveal hot gases. T
    10·2 answers
  • You make an online purchase of a hooded sweatshirt with the logo of the Dallas Cowboys. The next time you log on, your screen ha
    9·1 answer
  • Consider the following method, which is intended to return the index of the first negative integer in a given array of integers.
    14·1 answer
  • An independent penetration testing company is invited to test a company's legacy banking application developed for Android phone
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!