Answer:
m(x)
Step-by-step explanation:
they would have to pass the horizontal line test and the vertical line test for both the origional and the inverse.
b(x) does not pass the horizontal line test in any of the y values over 3
d(x) does not pass the horizontal line test for y=-9
p(x) does not pass the horizontal line test for positive y values
and m(x) has only one corresponding x value for every y value
Honestly I don't know congruent so congrats I can't answer sorry
Answer:
Ok, as i understand it:
for a point P = (x, y)
The values of x and y can be randomly chosen from the set {1, 2, ..., 10}
We want to find the probability that the point P lies on the second quadrant:
First, what type of points are located in the second quadrant?
We should have a value negative for x, and positive for y.
But in our set; {1, 2, ..., 10}, we have only positive values.
So x can not be negative, this means that the point can never be on the second quadrant.
So the probability is 0.
Answer:
I cant see the picture
Step-by-step explanation:
