Adult ticket= $6.00 Child ticket= $3.00
Total=$168.00
$6 x 17 people=$102 $3.00 x 17 kids= $51 + 5 kids x$3=$168
Adult tickets sold= 17
Children's Tickets sold= 22
There are 4 possible genotypes among any offspring (2 possible alleles from either A1 or A3, and 2 possible alles from either A2 or A4; 2*2=4), all of which are equally likely to occur with probability 1/4.
The probability that 2 offspring have the same genotype is (1/4)^2 = 1/16.
Is there supposed to be a picture i don’t see one
Answer:
1/6 is your answer ☺️☺️☺️
Answer: the solutions are
x = 3 or x = - 11
Step-by-step explanation:
The given quadratic equation is expressed as
y = 2x² + 16x - 66 = 0
The equation is already in the standard form of ax² + bx + c
The general formula for solving quadratic equations is expressed as
x = [- b ± √(b² - 4ac)]/2a
From the equation given,
a = 2
b = 16
c = - 66
Therefore,
x = [- 16 ± √(16² - 4 × 2 × - 66)]/2 × 2
x = [- 16 ± √(256 + 528)]/4
x = [- 16 ± √784]/4
x = (- 16 + 28)/4 or x = (- 16 - 28)/4
x = 12/4 or x = - 44/4
x = 3 or x = - 11