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Aleonysh [2.5K]
3 years ago
5

HELP ASAP FIRST RIGHT GET BRAINLEST

Mathematics
2 answers:
My name is Ann [436]3 years ago
7 0

Answer:

A

Step-by-step explanation: hope it helps

Naddik [55]3 years ago
7 0

Answer:

-5/6

Step-by-step explanation:

-\frac{5}{7} is then multiplied by the reciprocal

-\frac{5}{7}*\frac{7}{6} cross cancel the sevens

-\frac{5}{6\\} is your answer

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Mia has $40 in a savings account. She will start adding $5 to her account each week. Juan has $15 in a savings account. He will
tensa zangetsu [6.8K]
Y=40+5x
For an example, say Mia wanted to add $5 into her account each week for 2 weeks.
y=40+5(2)
5(2)=10
y=40+10
y=50
Mia will have a total of $50 in her account if she added $5 for each week for 2 weeks. Same for Juan, his equation will be based off his amount y=15+10x
4 0
3 years ago
A brownie recipe asks for three and one half times as much sugar as chocolate chips. If four and two thirds cups of sugar is use
Svetradugi [14.3K]

Answer:

1 1/3 chocolate chips

Step-by-step explanation:

you have to divide 4 2/3 ÷ 3 1/2

change mixed number to improper fraction

14/3÷7/2

KFC-Keep Flip Change

14/3 × 2/7 = 28/21

28÷21= 1 1/3

4 0
3 years ago
(+×9)(×-2) can some one solve it
marshall27 [118]
X2 - 2x + 9x - 18
X2 + 7x - 18
4 0
3 years ago
A heavy rope, 50 ft long, weighs 0.6 lb/ft and hangs over the edge of a building 120 ft high. Approximate the required work by a
Anastasy [175]

Answer:

Exercise (a)

The work done in pulling the rope to the top of the building is 750 lb·ft

Exercise (b)

The work done in pulling half the rope to the top of the building is 562.5 lb·ft

Step-by-step explanation:

Exercise (a)

The given parameters of the rope are;

The length of the rope = 50 ft.

The weight of the rope = 0.6 lb/ft.

The height of the building = 120 ft.

We have;

The work done in pulling a piece of the upper portion, ΔW₁ is given as follows;

ΔW₁ = 0.6Δx·x

The work done for the second half, ΔW₂, is given as follows;

ΔW₂ = 0.6Δx·x + 25×0.6 × 25 =  0.6Δx·x + 375

The total work done, W = W₁ + W₂ = 0.6Δx·x + 0.6Δx·x + 375

∴ We have;

W = 2 \times \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= 2 \times \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 750

The work done in pulling the rope to the top of the building, W = 750 lb·ft

Exercise (b)

The work done in pulling half the rope is given by W₂ as follows;

W_2 =  \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 562.5

The work done in pulling half the rope, W₂ = 562.5 lb·ft

6 0
2 years ago
Hello I really need help with this
Harman [31]

Answer:

<u>7</u>

Step-by-step explanation:

The sides are in proportion.

  • \frac{AC}{DF} = \frac{AB}{DE}
  • 35/? = 20/4
  • 35/? = 5
  • ? = 35/5
  • ? = <u>7</u>
5 0
2 years ago
Read 2 more answers
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