Find dy/dx if y= (x²-3)³cos2x
1 answer:
Answer:
dy/dx = 6x(x²-3)cos2x - 2(x²-3)³sin2x
Step-by-step explanation:
We use the Product Rule:
y= (x²-3)³cos2x
dy/dx = (x²-3)³ d(cos2x)/dx + cos2x * d ((x²-3)³)/dx
= (x²-3)³ * -2sin2x + cos2x * 3(x²-3)*2x
= -2sin2x*(x²-3)³ + 6xcos2x*(x²-3)
= 6x(x²-3)cos2x - 2(x²-3)³sin2x
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