The answer is 7/69.
There are 8 black-haired children among 24 children. The probability of <span>randomly selecting black haired children for the first time is:
P1 = 8/24 = 1/3
Now, there are 7 black-haired children left among 23 children. The probability of </span>randomly selecting black haired children for the second time is:
P2 = 7/23
Since we want both of these events to occur together, we will multiply their probabilities:
P = P1 * P2 = 1/3 * 7/23 = 7/69
Answer:
yesss
Step-by-step explanation:
The distance formula is: d = sqrt( (x2 - x1)2 + (y2 - y1)2 )
For this problem, let (-5, -4) be the "first" point, so x1 = -5 and y2 = -4
and let (-6, 4) be the "second" point, so x2 = -6 and y2 = 4.
Then: d = sqrt( (-6 - -5)2 + (4 - -4)2 ) = sqrt( (-1)2 + (8)2 ) = sqrt( 1 + 64 ) = sqrt( 65)
The distance formula is just the Pythagorean Theorem applied to an x-y graph.
You would get the same final answer if you let (-5, -4) be the second point and (-6, 4) be the first point.
What you need to do is give these problems a common denominator. Which makes 3/21 and14/21 respectively. Logically, you need to walk 4/21 of the trail. This can’t be simplified further.
