Answer:
Hazel will have knitted 25 centimeters of the scarf
SOLUTION
Problem Statement
We are told Hazel knits 5 centimeters of scarf every night for 5 nights. We are required to find the length of the scarf Hazel will have knitted after 5 nights.
Solution
We are told Hazel makes 5 centimeters of scarf every night. Thus, for each night up till 5 nights, we just need to add the length of scarf Hazel has made.
Let us count for each night.
Night 1:
Hazel makes 5 centimeters of the scarf.
Night 2:
Hazel makes extra 5 centimeters, which means she has made:
Night 3:
Hazel makes extra 5 centimeters, which means she has made:
NIght 4:
Hazel makes extra 5 centimeters, which means she has made:
NIght 5:
Hazel makes extra 5 centimeters, which means she has made:
Final Answer
Thus, Hazel will have knitted 25 centimeters of the scarf
The range is: 35-60
The IQR is: 11
This value is the first 25%
IQR= interquartile range
Hope this helps ;)
Answer:
Wednesday is 45 to 18.
Thursday is 55 to 22
Step-by-step explanation:
Wednesday: The original ratio was 5 to 2 And the info tells us that the new ratio is ? to 18. To find the first part we have to find how we got from 2 to 18. 2 * 9 = 18. So to find out the first part you do 5 * 9 = 45. We multiply 5 because Thats the original 1st part. We multiply 9 because that's how we got to 18 in the 2nd part. So the answer is 45 for Wednesday.
Thursday: The original ratio was 5 to 2 And the info tells us that the new ratio is 55 to ?. To find the first part we have to find how we got from 5 to 55. 5 * 11 = 55. So to find out the 2nd part you do 2 * 11 = 55. We multiply 2 because That's the original 2nd part. We multiply 11 because that's how we got to 55 in the 1st part. So the answer is 22 for Thursday.
<u>Question:</u>
Find the number of real number solutions for the equation. x^2 + 5x + 7 = 0
<u>Answer:</u>
The number of real solutions for the equation 
is zero
<u>Solution:</u>
For a Quadratic Equation of form : 
---- eqn 1
The solution is 
Now , the given Quadratic Equation is ---- eqn 2
On comparing Equation (1) and Equation(2), we get
a = 1 , b = 5 and c = 7
In , 
is called the discriminant of the quadratic equation
Its value determines the nature of roots
Now, here are the rules with discriminants:
1) D > 0; there are 2 real solutions in the equation
2) D = 0; there is 1 real solution in the equation
3) D < 0; there are no real solutions in the equation
Now let solve for given equation
Since -3 is less than 0, this means that there are 0 real solutions in this equation.
