What is it
I don't get it done
Note: The height of the room must be 3 m instead of 3 cm because 3 cm is too small and it cannot be the height of a room.
Given:
Perimeter of the floor of a room = 18 metre
Height of the room = 3 metre
To find:
The area of 4 walls of the room.
Solution:
We know that, the area of 4 walls of the room is the curved surface area of the cuboid room.
The curved surface area of the cuboid is

Where, h is height, l is length and b is breadth.
Perimeter of the rectangular base is 2(l+b). So,

Putting the given values, we get


Therefore, the area of 4 walls of the room is 54 sq. metres.
They are called unike fractions. If u would want to do anything to them u would have to make the denominaters the same
Answer:
The answer is C. 10
Step-by-step explanation:
Answer:
f (x) = -2 (x + 6)^2 + 2
Step-by-step explanation:
f (x) = -2x^2 - 24x - 70 <--- divide out -2 out of the first two terms...
f (x) = -2 (x^2 + 12x) - 70 <-- divide the x coefficient by 2 and then square it, then add AND subtract it)
f (x) = -2 (x^2 + 12x + (12/2)^2 - (12/2)^2) - 70
f (x) = -2 (x^2 + 12x + 36 - 36) - 70 <--- distribute the -2 onto -36 to get it out of the brackets..
f (x) = -2 (x^2 + 12x + 36) + 72 - 70 <-- combine constants and factor perfect square trinomial...
f (x) = -2 (x + 6)^2 + 2 <-- standard form...