Question

A coordinate plane.

Answer 1

Answer: D. (5, 4)

Step-by-step explanation:

An x-intercept of -1 means the point = (-1, 0)

So find the slope(m) using the formula: $\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$(x_{1},y_{1})=(-4,-2)\\(x_{2},y_{2})=(-1,0)\\\\m = \frac{0-(-2)}{-1-(-4)}=\frac{0+2}{4-1}=\frac{2}{3}$

Now find the y-intercept(b) by substituting a point into the function:

y = mx + b

$y=\frac{2}{3} x+b\\\\0=\frac{2}{3} (-1)+b\\\\0=-\frac{2}{3}+b\\\\b=\frac{2}{3}$

So now the function is determined as $y=\frac{2}{3} x+\frac{2}{3}=\frac{2}{3}(x+1)$.

Bring each of the coordinates in to see if it fits in:

A. (-6, -5)  $\frac{2}{3}(-6+1)=\frac{2}{3}(-5)=-3.33\neq -5$

B. (3, 2) $\frac{2}{3}(3+1)=\frac{2}{3}(4)=2.67\neq 2$

C. (4, 5) $\frac{2}{3}(4+1)=\frac{2}{3}(5)=3.33\neq 5$

D. (5, 4) $\frac{2}{3}(5+1)=\frac{2}{3}(6)=4$

Answer 2

Answer:

D(5,4)

Step-by-step explanation:

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