Answer:
8% or 0.08
Step-by-step explanation:
Probability of missing the first pass = 40% = 0.40
Probability of missing the second pass = 20% = 0.20
We have to find the probability that he misses both the passes. Since the two passes are independent of each other, the probability that he misses two passes will be:
Probability of missing 1st pass x Probability of missing 2nd pass
i.e.
Probability of missing two passes in a row = 0.40 x 0.20 = 0.08 = 8%
Thus, there is 8% probability that he misses two passes in a row.
I think the graph below is correct.
Angle ADC and EDG are congruent(vertical angles)
Same side interior angles are =180
2x+4x-30=180
6x-30=180
6x=210
x=35
CDG is congruent to DGH(alternate interior)
4x-30
4(35)-30
140-30
=110
Answer:
Step-by-step explanation:
its wierd but 2.22
