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3 years ago

Can someone help me

Mathematics

1 answer:

Sladkaya [172]3 years ago

5 0

'D' is correct as it is the only answer which includes commas when listing the characters and before "all of whom"
Try saying the sentence out loud and hearing where a pause is necessary.

Hope this helped!

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How Do I find log (y) equation

lord [1]

Mathematically, logₓ (y) is the number to which you raise 'x' in order to get 'y'.

Since logarithm to base 10 (that is, x = 10) is the common logarithm,
log (y) is same as log₁₀ (y).

Therefore, log (y) is the number to which you raise 10 in order to get 'y'.

6 0

3 years ago

Help with this question plz I need the answer plz help me plz

maria [59]

It's C.

All the other options are a 3 to 1 ratio, except for C.

5 0

4 years ago

If AC = 14, what is the measure of AD? Round your answer to the nearest hundredth.

nikklg [1K]

Part A

Answer: Choice D) $\text{AD} = \sqrt{(2n+5)^2+(4n-3)^2}$

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Explanation:

Let E be the intersection point of the diagonals. For any parallelogram, the diagonals bisect each other. This means that AE = EC = 2n+5 and it also means EB = DE = 4n-3

Focus on triangle AED. This triangle is a right triangle with angle AED as a 90 degree angle (any rhombus has its diagonals that are perpendicular to one another). The legs of this triangle are AE = 2n+5 and ED = 4n-3

Apply the pythagorean theorem to find hypotenuse AD

$(\text{leg1})^2+(\text{leg2})^2 = (\text{hypotenuse})^2\\\\(\text{AE})^2+(\text{ED})^2 = (\text{AD})^2\\\\(\text{AD})^2 = (\text{AE})^2+(\text{ED})^2\\\\\text{AD} = \sqrt{(\text{AE})^2+(\text{ED})^2}\\\\\text{AD} = \sqrt{(2n+5)^2+(4n-3)^2}\\\\$

This points to choice D as the final answer.

===========================================================

Part B

<h3>Answer: 7.07</h3>

-----------------------------------------------

Explanation:

If AC = 14, then half of this is AE = 7. The diagonals bisect each other, so they cut each other in half with E at the midpoint.

Since AE = 2n+5, we can solve for n like so

2n+5 = 7

2n = 7-5

2n = 2

n = 2/2

n = 1

Then we can find the length of AD

$\text{AD} = \sqrt{(2n+5)^2+(4n-3)^2}\\\\\text{AD} = \sqrt{(2*1+5)^2+(4*1-3)^2}\\\\\text{AD} = \sqrt{(2+5)^2+(4-3)^2}\\\\\text{AD} = \sqrt{7^2+1^2}\\\\\text{AD} = \sqrt{49+1}\\\\\text{AD} = \sqrt{50}\\\\\text{AD} \approx 7.0710678\\\\\text{AD} \approx 7.07\\\\$

Segment AD is roughly 7.07 units long. The other external sides of the rhombus (AB, BC and CD) are also this length because the four sides of any rhombus are the same length.

7 0

3 years ago

Help please with math

quester [9]

Working with fractions, huh? They are not as hard as you may think.

Just think:

1/4 = 2/8

3/4= 6/8

So...

9 3/4 = 9 6/8

Step 2.

9 + 1 = 10

6/8 + 1/8 = 7/8

Step 3

10 and 7/8

Step 4

Simplest answer
10 7/8,
(can't get more simplified than that)

Hope this helps! :)

7 0

4 years ago

Read 2 more answers

Johnny has a box filled with 10 black marbles and 5 purple marbles what are the odds he pulls to black marbles in a row?

Licemer1 [7]

Answer:

3/7

Step-by-step explanation:

The first black marble is 10/15 and the second is 9/14. Multiply them together to get 3/7 after you simplify it.

4 0

3 years ago