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Tju [1.3M]
3 years ago
10

What is an example of Big Data?

Computers and Technology
1 answer:
Y_Kistochka [10]3 years ago
6 0

Answer:

providing real-time data feeds on millions of people with wearable devices

Explanation:

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How many pieces are there in a normal laptop??? Good luck and solve carefully
polet [3.4K]

What do you mean pieces? Like Laptop components? If so then motherboard,ram,cpu, and psu for a basic laptop so 4 I guess (5 if you want to include a gpu).

4 0
3 years ago
Briefly list four of the basic I/O interface standard? ​
tiny-mole [99]

Four of the basic I/O interface standard are PCI, SCSI, USB and ISA.

<h3>Standard I/O Interface</h3>

Input-Output Interface is used as an method which helps in transferring of information between the internal storage devices. A number of standards have been developed for I/O Interface.

There widely used bus standards are:

  • PCI (Peripheral Component Interconnect)
  • SCSI (Small Computer System Interface), and
  • USB (Universal Serial Bus).
  • ISA (Industry Standard Architecture)

Find out more on Standard I/O Interface at: brainly.com/question/24347579

4 0
3 years ago
In Java, a char variable is capable of storing any Unicode character. Write a statement that assigns the Greek letter ^ to a cha
miv72 [106K]

Answer:

public class Main

{

public static void main(String[] args) {

    char greekLetter = '^';

    System.out.println(greekLetter);

}

}

Explanation:

Create a char variable called greekLetter and set it to the ^

Print the greekLetter to the screen

7 0
3 years ago
Consider two different implementations, M1 and M2, of the same instruction set. There are three classes of instructions (A, B, a
ANTONII [103]

Answer:

a) the average CPI for machine M1 = 1.6

the average CPI for machine M2 = 2.5

b) M1 implementation is faster.

c) the clock cycles required for both processors.52.6*10^6.

Explanation:

(a)

The average CPI for M1 = 0.6 x 1 + 0.3 x 2 + 0.1 x 4

= 1.6

The average CPI for M2 = 0.6 x 2 + 0.3 x 3 + 0.1 x 4

= 2.5

(b)

The average MIPS rate is calculated as: Clock Rate/ averageCPI x 10^6

Given 80MHz = 80 * 10^6

The average MIPS ratings for M1 = 80 x 10^6  / 1.6 x 10^6

= 50

Given 100MHz = 100 * 10^6

The average MIPS ratings for M2 = 100 x 10^6 / 2.5 x 10^6

= 40

c)

Machine M2 has a smaller MIPS rating

Changing instruction set A from 2 to 1

The CPI will be increased to 1.9 (1*.6+3*.3+4*.1)

and hence MIPS Rating will now be (100/1.9)*10^6 = 52.6*10^6.

7 0
3 years ago
Which of the following is a domestic business activity?
harkovskaia [24]
What are the options?

7 0
3 years ago
Read 2 more answers
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