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Flauer [41]
4 years ago
9

Security and protection as it relates to operating systems is grouped into four categories: Availability, Data integrity, Authen

ticity, and ___________.
Computers and Technology
1 answer:
Ivahew [28]4 years ago
4 0

Answer:

The answer is "Confidentiality".

Explanation:

Data Security is also known as protection against unauthorized computer access, files, and pages through digital information protection. The protection of data also prevents data from bribery.  

  • It applies to both the security of data from unwanted entities being obtained.
  • It allows accessing sensitive data, which may be able to do so.
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public class Test { public static void main(String[] args) { try { method(); System.out.println("After the method call"); } catc
USPshnik [31]

Answer:

"ArithmeticException" is the correct answer for the above question.

Explanation:

Missing Information : The above question does not hold that "what is the output of the program".

  • The above question has a class that holds the two functions one function is the main function which calls the other function in a try-catch block.
  • The method function holds one run time exception which is 1/0 which is an arithmetic exception.
  • It can be handle by the help of an arithmetic class object which is defined in the first catch block.
  • Hence the print function of this catch is executed and prints "ArithmeticException".
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3 years ago
What's wrong with the coding worksheet syntax and how would you fix it?
Alex777 [14]

Answer:

start with what you know

Explanation:

3 0
3 years ago
Write a program that reads a list of integers, and outputs the two smallest integers in the list, in ascending order. The input
kompoz [17]

Answer:

Following are the program in the C++ programming Language.

//header files

#include <iostream>

#include <vector>

using namespace std;//name space

// define main method

int main()

{

//set integer variables

int size, num;

//get input the size of the list

cout<<"Enter size of list: ";

cin >> size;

//set integer type vector variable

vector<int> vecs;

//Set the for loop

for (int index = 0; index < size; ++index)

{//get elements of the list from the user

cout<<" :";

cin >> num;

//push back the elements of the list

vecs.push_back(num);

}

//storing the first two elements in variable

int n = vecs[0], n1 = vecs[1], current , temp;

//set if conditional statement

if (n > n1)

{

//perform swapping

temp = n;

n = n1;

n1 = temp;

}

//Set for loop

for (int index = 2; index < size; ++index)

{

//store the value of the vector in the variable

current = vecs[index];

//set if conditional statement

if (current < n)

{

//interchange the elements of the variable

n1 = n;

n = current;

}

else if(current < n1)

{

n1 = current;

}

}

//print the value of first two smallest number.

cout <<"\n" <<n << " " << n1 << endl;

return 0;

}

<u>Output:</u>

Enter size of list: 5

:10

:5

:3

:21

:2

2 3

Explanation:

Here, we define the required header files and namespace then, we define "main()" function inside the main function.

  • Set two integer data type variable "size", "num".
  • Print message and get input from the user in variable  "size".
  • Then, we set integer vector type variable "vecs".
  • Set the for loop to get the number of input in the variable "num" from user.
  • Then, we push back the elements of the list and store first two elements of the list in the variable "n", "n1".
  • Set the conditional statement to perform swapping.
  • Define the for loop to store the list of the vector in the integer type variable "current".
  • Finally, we print the value of the two smallest numbers of the list.
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I believe the answer could be the first choice. I'm not quite sure, though
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