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tiny-mole [99]
3 years ago
6

Solve the given inequality 11x-20<_13​

Mathematics
2 answers:
Lunna [17]3 years ago
7 0

\huge{ \mathfrak{ Answer }}

  • 11x - 20 \leqslant 13

  • 11x  \leqslant  20 + 13

  • x  \leqslant  33 \div 11

  • x \leqslant 3

\#TeeNForeveR

RUDIKE [14]3 years ago
3 0

Answer:

x ≤ 3

Step-by-step explanation:

11

x

−

20

≤

13

Step 1: Add 20 to both sides.

11

x

−

20

+

20

≤

13

+

20

11

x

≤

33

Step 2: Divide both sides by 11.

11

x

11

≤

33

11

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blondinia [14]
You are multiply by -2.
term 1: 5
term 2: -10
terms 3: 20
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term 5: 80
term 6: -160
term 7: 320
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What is the length of the hypotenuse in a right triangle with legs of length 7 and 24?
Fiesta28 [93]
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4 0
3 years ago
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3 years ago
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6 0
3 years ago
How does one find the inverse function of f(x)= <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3x-1%7D" id="TexFormula1" tit
lisabon 2012 [21]

Answer:

\displaystyle f^{-1}(x)=\frac{1+x}{3x}

Step-by-step explanation:

<u>The Inverse of a Function</u>

The procedure to find the inverse of the function is:

* Write the function as a two-variable equation:

\displaystyle y=\frac{1}{3x-1}

* Solve the equation for x.

Multiply by 3x-1

y(3x-1)=1

Divide by y:

\displaystyle 3x-1=\frac{1}{y}

Sum 1:

\displaystyle 3x=\frac{1}{y}+1

Operate the right side:

\displaystyle 3x=\frac{1+y}{y}

Divide by 3:

\displaystyle x=\frac{1+y}{3y}

* Swap the variables:

\displaystyle y=\frac{1+x}{3x}

Write back into function form:

\boxed{\displaystyle f^{-1}(x)=\frac{1+x}{3x}}

7 0
3 years ago
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