The answer to this problem is 4
Answer:
Yes , function is continuous in [0,2] and is differentiable (0,2) since polynomial function are continuous and differentiable
Step-by-step explanation:
We are given the Function
f(x) =
The two basic hypothesis of the mean valued theorem are
- The function should be continuous in [0,2]
- The function should be differentiable in (1,2)
upon checking the condition stated above on the given function
f(x) is continuous in the interval [0,2] as the functions is quadratic and we can conclude that from its graph
also the f(x) is differentiable in (0,2)
f'(x) = 6x - 2
Now the function satisfies both the conditions
so applying MVT
6x-2 = f(2) - f(0) / 2-0
6x-2 = 9 - 1 /2
6x-2 = 4
6x=6
x=1
so this is the tangent line for this given function.
5*(143)
=5*(100+40+3)
=5(100)+5(40)+5(3)
=500+200+15
=715
Hope this helps!
Your fortune is "Be careful of who you choose to be with."
1/6 of 18 is 3
1/9 of 18 is 2
3+2= 5
He lent 5 markets in total
<span>We have to draw a figure with a perimeter 6 units. If we want to draw a rectangle it can`t be a 3 by 2 because it has a perimeter 2*2 + 2*3 = 4 + 6 = 10 units. It must be a 2 by 1 rectangle ( 2*2 + 2*1 = 4 + 2 = 6 units ).</span>