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seraphim [82]
3 years ago
13

Help pls I really need this

Mathematics
1 answer:
Varvara68 [4.7K]3 years ago
7 0

Answer:

{2 , 4} is the answer of this question.

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Unit 22. Practice test
OLga [1]

Answer:

D

Step-by-step explanation:

5 0
3 years ago
Search cos jk and tan jk knowing that sin jk = 8/3
aleksley [76]

Answer:

cosjk = √55 i/3

tanjk = 8/√55 i

Step-by-step explanation:

Given

sin jk = 8/3

According to SOH CAH TOA

Sin theta = opposite/hypotenuse = 8/3

Opposite = 8

hypotenuse = 3

Get the adjacent using the pythagoras theorem

hyp² = opp²+adj²

adj² = hyp² - opp²

adj² = 3² - 8²

adj² = 9-64

adj² = -55

adj = √-55

adj = √55 i (i = √-1)

Get cosjk

cosjk = adj/hyp

cosjk = √55 i/3

Get tanjk

tanjk = opp/adj

tanjk = 8/√55 i

3 0
3 years ago
How do you solve y= -3+3​
Ilia_Sergeevich [38]
Answer=

y=-3+3
y=0

the sum of -3+3 is zero.
6 0
3 years ago
Which expressions would complete this equation so that it has infinitely many solutions? 8 + 2(8x – 6) = Choose exactly two answ
cupoosta [38]
<span> the answers are ...C. 16x – 4 and  D. 4(4x – 1) ...

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3 0
3 years ago
X=6{2+3[2(7-3)+(7+1)-5]} can someone help?
erma4kov [3.2K]

270 solve that yourself lol

3 0
2 years ago
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