The value of (f - g)(x) is as follows:
(f - g)(x) = 4x³ + 6x² - 7x - 1
<h3>How to solve functions?</h3>
f(x) = 4x³ + 6x² - 3x - 4
g(x) = 4x - 3
Let's find the function:
(f - g)(x)
Therefore,
(f - g)(x) = 4x³ + 6x² - 3x - 4 - ( 4x - 3)
Hence, let's open the bracket
(f - g)(x) = 4x³ + 6x² - 3x - 4 - 4x + 3
Let's combine like terms
(f - g)(x) = 4x³ + 6x² - 3x - 4x - 4 + 3
Therefore,
(f - g)(x) = 4x³ + 6x² - 7x - 1
learn more on function here: brainly.com/question/27951994
#SPJ1
In a 45-45-90 triangle, the two legs are congruent. Let's call them x. The hypotenuse is equal to 1 as we're using the unit circle. The hypotenuse of the triangle is the same as the radius of the unit circle.
a = x
b = x
c = 1
Use those values in the Pythagorean theorem to solve for x.
a^2 + b^2 = c^2
x^2 + x^2 = 1^2
2x^2 = 1
x^2 = 1/2
x = sqrt( 1/2 )
x = sqrt(1)/sqrt(2)
x = 1/sqrt(2)
x = sqrt(2)/2 ... rationalizing the denominator
So this right triangle has legs that are sqrt(2)/2 units long. Once we know the legs of the triangle, we can divide them over the hypotenuse to find the sine and cosine values.
sin(angle) = opposite/hypotenuse
sin(45) = (sqrt(2)/2) / 1
sin(45) = sqrt(2)/2
and
cos(angle) = adjacent/hypotenuse
cos(45) = (sqrt(2)/2) / 1
cos(45) = sqrt(2)/2
------------------------------------------------------
For a 30-60-90 triangle, we would have
a = 1
b = x
c = 2
so,
a^2+b^2 = c^2
1^2+x^2 = 2^2
1+x^2 = 4
x^2 = 4-1
x^2 = 3
x = sqrt(3)
The missing leg is sqrt(3) units long.
Once we know the three sides of the 30-60-90 triangle, you should be able to see that
sin(30) = 1/2
sin(60) = sqrt(3)/2
cos(30) = sqrt(3)/2
cos(60) = 1/2
Answer:
what this question make NO sence. please elaborate.
Step-by-step explanation:
Triangular prism
length of slanted side:
sqrt(3^2 + 4^2) = 5
SA = 2(1/2)(8)(3) + 8(12) + 2(5)(12) =240
V = (1/2)(8)(3)(12) = 144
cuboid
SA = 2(7x6) + 2(7x5) + 2(6x5) = 214
V = 7x6x5 = 210
