Answer:
the value of b is 3
I think
<h2><u>hope</u><u> </u><u>it</u><u> </u><u>helped</u><u> </u></h2>
Center : Mean Before the introduction of the new course, center = average(121,134,106,93,149,130,119,128) = 122.5 After the introduction of the new course, center = average(121,134,106,93,149,130,119,128,45) = 113.9 The center has moved to the left (if plotted in a graph) because of the low intake for the new course. Spread before introduction of the new course : Arrange the numbers in ascending order: (93, 106,119, 121), (128, 130,134, 149) Q1=median(93,106,119,121) = 112.5 Q3=median(128,130,134,149) = 132 Spread = Interquartile range = Q3-Q1 = 19.5 After addition of the new course,
(45,93, 106,119,) 121, (128, 130,134, 149)
Q1=median(45,93,106,119)=99.5
Q3=median (128, 130,134, 149)= 132
Spread = Interquartile range = 132-99.5 =32.5
We see that the spread has increased after the addition of the new course.
Answer:
15°
Step-by-step explanation:
The 165° and <em>x</em> forms a straight line or a supplementary angle. Supplementary angles add up to 180°. Therefore:
Solve for <em>x:</em>
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Answer: See explanation: 10, 1, 1, -7
Step-by-step explanation:
I'll assume you are working with Excel. The Product function multiplies all the cells given in the specified range. Here, those are cells A2 through A5. As presnted, this would be [10*5*0*(-7)] = 0, which is the value of cell B2. If we want cell B2 to be -70, we must change one or more of the numbers in cells A2 to A5.
Initial: 10, 5, 0, -7 B2=0
Change: 10, 1, 1, -7 B2 = -70
Other combinations are possible.
