Answer:
The volume of the sphere is 14m³
Step-by-step explanation:
Given
Volume of the cylinder = 
Required
Volume of the sphere
Given that the volume of the cylinder is 21, the first step is to solve for the radius of the cylinder;
<em>Using the volume formula of a cylinder</em>
The formula goes thus

Substitute 21 for V; this gives

Divide both sides by h


The next step is to solve for the volume of the sphere using the following formula;

Divide both sides by r

Expand Expression

Substitute 



Multiply both sided by r

------ equation 1
From the question, we were given that the height of the cylinder and the sphere have equal value;
This implies that the height of the cylinder equals the diameter of the sphere. In other words
, where D represents diameter of the sphere
Recall that 
So, 

Substitute 2r for h in equation 1



Hence, the volume of the sphere is 14m³
Answer:
The answer is b. 343,480.8ft
Step-by-step explanation:
I thought it was c at first because I forgot to add the volume of the cone.
The equation for the volume of a cylinder is V=π×r²×h
The solution would look like V=π40²×65=326725.8
The equation for the volume of a cone is V=1/3πr²×h
The solution would look like V=1/3π×40²×10=16755
Adding the two volumes would equal 326725.8±16755= 343480.8
Answer:

Domain: All Real Numbers
General Formulas and Concepts:
<u>Algebra I</u>
- Domain is the set of x-values that can be inputted into function f(x)
<u>Calculus</u>
The derivative of a constant is equal to 0
Basic Power Rule:
- f(x) = cxⁿ
- f’(x) = c·nxⁿ⁻¹
Chain Rule: ![\frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%5Bf%28g%28x%29%29%5D%20%3Df%27%28g%28x%29%29%20%5Ccdot%20g%27%28x%29)
Derivative: ![\frac{d}{dx} [ln(u)] = \frac{u'}{u}](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%20%5Bln%28u%29%5D%20%3D%20%5Cfrac%7Bu%27%7D%7Bu%7D)
Step-by-step explanation:
<u>Step 1: Define</u>
f(x) = ln(2x² + 1)
<u>Step 2: Differentiate</u>
- Derivative ln(u) [Chain Rule/Basic Power]:

- Simplify:

- Multiply:

<u>Step 3: Domain</u>
We know that we would have issues in the denominator when we have a rational expression. However, we can see that the denominator would never equal 0.
Therefore, our domain would be all real numbers.
We can also graph the differential function to analyze the domain.
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