The slope of this line is:
3-(-6)
m = ------------ = 1
3-(-3)
and so, using the point-slope formula for the equation of a str. line,
y-3 = 1(x-3), or y-3 = x - 3, or 1x - 3 - y + 3 = 0. Then 1x - 1y = 0 (in standard form). Alternatively, y = x (slope-intercept form).
Important:
The sum of the three angles inside
every triangle is always 180°.
First, look at the left triangle alone.
Two of its angles are 46° and 58° . (46° + 58° ) = 104°
That leaves (180° - 104° ) = 76° degrees for the third angle.
The third angle in that triangle is 'x'.
x = 76° .
At the point where 'x' and 'z' come together:
'x' and 'z' are a "linear pair".
Placed side-by-side, they form a straight line.
So (x + z) = 180° .
But x = 76°.
So z = (180° - 76°). z = 104° .
Now look at the the skinny triangle on the right alone.
The angle at the top is 13°, and z = 104°.
(13° + 104°) = 117° .
That leaves (180° - 117°) = 63° for the third angle.
'y' is the third angle.
y = 63° .
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