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DIA [1.3K]
3 years ago
13

How many numbers between 10 and 199 having increasing digits from left to right? For example —34, 79, and 126. These are not —55

,1 22, and 171.
Mathematics
1 answer:
FromTheMoon [43]3 years ago
7 0

Answer:

probably at least 2

Step-by-step explanation:

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The pattern for a scarf is shown<br> at right what is the area of this car for use 3.14
Tems11 [23]

Answer:

area of circle=pi times radius^2

diameter/2=radius

area of rectangle=length times width

rectanlge-circle=scarf

rectanlge=28 by 15=28*15=420

circle, diameter is 15 so radius is 15/2=7.5

area=pi7.5^2=pi56.25=3.14*56.25=176.625

so

rectangle-circle=420-176.625=243.375 square inches

the area of the scarf is 243.375 square inches

Step-by-step explanation:

7 0
2 years ago
Please help!!!!!!!!!!!!!!!!!!
S_A_V [24]

Answer:

It should be the first one.


Step-by-step explanation:


8 0
3 years ago
Read 2 more answers
Two cars leave a town at the same time heading in opposite directions. One car is traveling 12 mph faster than the other. After
Katena32 [7]
<span>Find the speed of each car.
Let a be the first car
Let b be the second car
=> a = x miles per hour
=> b = x + 12 miles per hour
=> 2 (x+ x + 12) = 232 miles per hour
=> 2x + 12 = 232
=> 2x + 12 = 116
=> 2x = 116 - 12
=> 2x / 2 = 104 / 2
=> x = 52 (speed of Car A)
=> 52 + 12 = 64 miles per hour (speed of Car B)</span>



4 0
3 years ago
What is 0.002 1/10 of
ki77a [65]
<span>0.002 1/10 of what
=> 1/10a = 0.002
=> Now, let’s multiply both sides with 10 to find the answer since we’re looking for the 1/10 of what number.
=> 10 x 1/10 a = 10 x 0.002
=>  a = 0.02

Thus, 0.002 is the 1/10 of 0.02 number.
let’s check if we have a correct answer.
To check just do the other way around, Divide our answer by 10.
=> 0.02 / 10
=> 0.002
Therefore, our answer is correct

</span>



5 0
3 years ago
I have the first part but I don't know how to do the second part<br><br> h e l p
Debora [2.8K]

\bf \begin{array}{cll} \stackrel{ordinal}{position}&\stackrel{term}{value}\\ \cline{1-2} 1&12\\ 2&12+d\\ 3&12+d+d\\ 4&12+d+d+d\\ &12+3d \end{array}\qquad \implies ~\hfill \begin{array}{llll} \stackrel{\textit{4th term}}{12+3d}~~=~~\stackrel{\textit{4th value}}{3}\\\\ 3d=-9\implies d = \cfrac{-9}{3}\\\\ \stackrel{\textit{common difference}}{d = -3} \end{array}

well, we know the common difference is -3, to go from the 4th term to the 8th term, we need to add "d" 4 times or namely 3+4(-3), likewise to go from the 13th term to the 19th term we have to add "d" 6 times, or namely -24 + 6(-3).

\bf \stackrel{\textit{8th term}}{3+4(-3)}\implies 3-12\implies -9 \\\\\\ \stackrel{\textit{19th term}}{-24 + 6(-3)}\implies -24-18\implies -42

3 0
3 years ago
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