We have been given in a cohort of 35 graduating students, there are three different prizes to be awarded. We are asked that in how many different ways could the prizes be awarded, if no student can receive more than one prize.
To solve this problem we will use permutations.
We know that formula for permutations is given as
On substituting the given values in the formula we get,
Therefore, there are 39270 ways in which prizes can be awarded.
Answer:
The answer to your question is the last option
Step-by-step explanation:
Quadratic equation
2 = - x + x² - 4
Order the equation from the highest power to the lowest power. Do not consider 2 because it is not consider in the options given.
x² - x - 4 = 0
Identify a, b and c
(1) x² -(1) x - 4 = 0
a = 1 b = -1 c = - 6
Substitution
Answer:
27in
Step-by-step explanation:
So, perimeter means we add all the sides together, as opposed to area, where we multiply them together.
9 - 5 = 4.
So the perimeter of the triangle would be:
3+4+=12
5 + 5 + 4 +1 (the 1 is from 4 -3) = 15
15 + 12 = 27