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Effectus [21]
3 years ago
15

Jane is a computer science major planning to take 4 courses next semester. She is planning to take 2 computer science courses an

d 2 courses from other areas. How many different schedules can she build?
Mathematics
1 answer:
ddd [48]3 years ago
8 0

Answer: 24 schedules.

Step-by-step explanation:

Given data:

Courses planning to take = 4

Computer courses = 2

Courses from other areas = 2

Solution:

This problem can be solved using permutation.

For Computer science courses.

npr = n! / ( n - r )!

Where n = 4

r = 2

4p2 = 4!/( 4-2)!

= 4!/2!

= 12

For other courses.

Where n = 4

r = 2

4p2 = 4!/( 4-2)!

= 4!/2!

= 12

Jane can have a total of 24 different schedules.

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4 years ago
3[5x - 4] - [-30 - 45x]
Nimfa-mama [501]
3(5x - 4) - (-30-45x)
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