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shusha [124]
3 years ago
5

3[5x - 4] - [-30 - 45x]

Mathematics
2 answers:
quester [9]3 years ago
4 0

3[5x - 4] - [-30 - 45x] =<span />

<span>Simplifying 3[5x + -4] + -1[-30 + -45x] = 0 </span>

<span>Reorder the terms: 3[-4 + 5x] + -1[-30 + -45x] = 0 [-4 * 3 + 5x * 3] + -1[-30 + -45x] = 0 [-12 + 15x] + -1[-30 + -45x] = 0 -12 + 15x + [-30 * -1 + -45x * -1] = 0 -12 + 15x + [30 + 45x] = 0 </span>

<span>Reorder the terms: -12 + 30 + 15x + 45x = 0 </span>

<span>Combine like terms: -12 + 30 = 18 18 + 15x + 45x = 0 </span>

<span>Combine like terms: 15x + 45x = 60x 18 + 60x = 0 </span>

<span>Solving 18 + 60x = 0 </span>

<span>Solving for variable 'x'. </span>

<span>Move all terms containing x to the left, all other terms to the right. Add '-18' to each side of the equation. 18 + -18 + 60x = 0 + -18 </span>

<span>Combine like terms: 18 + -18 = 0 0 + 60x = 0 + -18 60x = 0 + -18 </span>

<span> Combine like terms: 0 + -18 = -18 60x = -18 </span>

<span> Divide each side by '60'. x = -0.3 </span>

<span> Simplifying x = -0.3
</span>

Nimfa-mama [501]3 years ago
3 0
3(5x - 4) - (-30-45x)
= 15x - 12 + 30 + 45x <- Distributive Property
=60x + 18 <- Combine Like Terms

If you're trying to solve for 0:

0 = 60 x + 18
-18 = 60x <- Subtracted 18 from both sides
x = \frac{-18}{60} = \frac{-9}{30} <- Divided both sides by 60 and then simplified.

x = \frac{-9}{30} <- Fraction Form
x = -0.3 <- Decimal Form

Give Brainliest for simple answer plz :P
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the cost of a soft drink varies directly with number of ounces you buy. IF 12 ounces cost $0.08 how many ounces of the soft drin
babunello [35]
30 ounces because 0.08 x 30=2.40
5 0
3 years ago
The following data summarizes results from 889 pedestrian deaths that were caused by accidents. If one of the pedestrian deaths
pickupchik [31]

Answer:

P(A or B) = 0.291 +0.159 -0.0562=0.3938

Step-by-step explanation:

Previous concepts

The total probability rule is "used to find the probability of an event, A, when you don’t know enough about A’s probabilities to calculate it directly. Instead, you take a related event, B, and use that to calculate the probability for A".

Solution to the problem

The data given:

                                                             Pedestrian

                                       Intoxicated                       Not intoxicated     Total          

Intoxicated                           50                                        91                    141

Not intoxicated                    209                                     539                 748

Total                                     259                                      630                889

The rows on this case are associated to the tyep of Driver.

Let's define the following events:

A =Pedestrian was intoxicated

B= Driver was intoxicated

And we can find the probabilities for the events A and B like this with the info given:

P(A) = \frac{50+209}{889}=0.291

P(B) = \frac{50+91}{889}=0.159

We can find also the probaility that pedestrian was intoxicated AND driver was ​intoxicated, like this:

P(A and B) = \frac{50}{889}=0.0562

Because the intersection for the events A and B is 50 and the grand total is 889.

Now we can use the total rule of probability given by this:

P(A or B) = P(A) +P(B) -P(A and B)

And since w ehave everything to replace we got:

P(A or B) = 0.291 +0.159 -0.0562=0.3938

7 0
3 years ago
Consider a rabbit population​ P(t) satisfying the logistic equation StartFraction dP Over dt EndFraction equals aP minus bP squa
maria [59]

Solution:

Given :

$\frac{dP}{dt}= aP-bP^2$         .............(1)

where, B = aP = birth rate

            D = $bP^2$  =  death rate

Now initial population at t = 0, we have

$P_0$ = 220 ,  $B_0$ = 9 ,  $D_0$ = 15

Now equation (1) can be written as :

$ \frac{dP}{dt}=P(a-bP)$

$\frac{dP}{dt}=bP(\frac{a}{b}-P)$    .................(2)

Now this equation is similar to the logistic differential equation which is ,

$\frac{dP}{dt}=kP(M-P)$

where M = limiting population / carrying capacity

This gives us M = a/b

Now we can find the value of a and b at t=0 and substitute for M

$a_0=\frac{B_0}{P_0}$    and     $b_0=\frac{D_0}{P_0^2}$

So, $M=\frac{B_0P_0}{D_0}$

          = $\frac{9 \times 220}{15}$

          = 132

Now from equation (2), we get the constants

k = b = $\frac{D_0}{P_0^2} = \frac{15}{220^2}$

        = $\frac{3}{9680}$

The population P(t) from logistic equation is calculated by :

$P(t)= \frac{MP_0}{P_0+(M-P_0)e^{-kMt}}$

$P(t)= \frac{132 \times 220}{220+(132-220)e^{-\frac{3}{9680} \times132t}}$

$P(t)= \frac{29040}{220-88e^{-\frac{396}{9680} t}}$

As per question, P(t) = 110% of M

$\frac{110}{100} \times 132= \frac{29040}{220-88e^{\frac{-396}{9680} t}}$

$ 220-88e^{\frac{-99}{2420} t}=200$

$ e^{\frac{-99}{2420} t}=\frac{5}{22}$

Now taking natural logs on both the sides we get

t = 36.216

Number of months = 36.216

8 0
4 years ago
HELPP
wolverine [178]

Answer:

It would\ be -7 F.

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
What the answer and how do I solve it?
tatiyna

Answer:

5xy^2z

Step-by-step explanation:

(-15/-3) x (x^6/x^5) x (y^5/y^3) x z = 5xy^2z

4 0
3 years ago
Read 2 more answers
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