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shusha [124]
3 years ago
5

3[5x - 4] - [-30 - 45x]

Mathematics
2 answers:
quester [9]3 years ago
4 0

3[5x - 4] - [-30 - 45x] =<span />

<span>Simplifying 3[5x + -4] + -1[-30 + -45x] = 0 </span>

<span>Reorder the terms: 3[-4 + 5x] + -1[-30 + -45x] = 0 [-4 * 3 + 5x * 3] + -1[-30 + -45x] = 0 [-12 + 15x] + -1[-30 + -45x] = 0 -12 + 15x + [-30 * -1 + -45x * -1] = 0 -12 + 15x + [30 + 45x] = 0 </span>

<span>Reorder the terms: -12 + 30 + 15x + 45x = 0 </span>

<span>Combine like terms: -12 + 30 = 18 18 + 15x + 45x = 0 </span>

<span>Combine like terms: 15x + 45x = 60x 18 + 60x = 0 </span>

<span>Solving 18 + 60x = 0 </span>

<span>Solving for variable 'x'. </span>

<span>Move all terms containing x to the left, all other terms to the right. Add '-18' to each side of the equation. 18 + -18 + 60x = 0 + -18 </span>

<span>Combine like terms: 18 + -18 = 0 0 + 60x = 0 + -18 60x = 0 + -18 </span>

<span> Combine like terms: 0 + -18 = -18 60x = -18 </span>

<span> Divide each side by '60'. x = -0.3 </span>

<span> Simplifying x = -0.3
</span>

Nimfa-mama [501]3 years ago
3 0
3(5x - 4) - (-30-45x)
= 15x - 12 + 30 + 45x <- Distributive Property
=60x + 18 <- Combine Like Terms

If you're trying to solve for 0:

0 = 60 x + 18
-18 = 60x <- Subtracted 18 from both sides
x = \frac{-18}{60} = \frac{-9}{30} <- Divided both sides by 60 and then simplified.

x = \frac{-9}{30} <- Fraction Form
x = -0.3 <- Decimal Form

Give Brainliest for simple answer plz :P
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Write the following series in sigma notation.<br> 7 + 16 + 25 +34 +43 +52 + 61
Solnce55 [7]

The series 7 + 16 + 25 +34 +43 +52 + 61 is an illusration of arithmetic series

The sigma notation of the series is: \sum\limits^7_{n=1} {9n - 2}

<h3>How to write the series in sigma notation?</h3>

The series is given as:

7 + 16 + 25 +34 +43 +52 + 61

The above series is an arithmetic series, with the following parameters

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Start by calculating the nth term using:

a(n) = a + (n - 1) * d

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So, the sigma notation is:

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