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gizmo_the_mogwai [7]
2 years ago
10

Round nearest hundredth​

Mathematics
1 answer:
maks197457 [2]2 years ago
4 0

Answer:.

Step-by-step explanation:nearest hundredth the answer for this question is joe mama

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F(x)=x^2 +10 Over which interval does f have a positive average rate of change?
EastWind [94]

Answer:

No x-intercept/Zero

Step-by-step explanation:

Substitute f (x)=0

Solve the equation

There is no x-intercept/zero

5 0
2 years ago
Read 2 more answers
Using the number 686293, what is the value of the digit 8
marysya [2.9K]

To find what the value of the digit 8 is, we can start by moving from the right. In a number, the place value goes (from right to left) ones, tens, hundreds, thousands, ten-thousands, hundred-thousands, millions and so on. Now we can find out what each of the numbers is.

Since 3 is the first, that means 3 is in the ones place.

Since 9 is second, that means that 9 is in the tens place.

Since 2 is third, that means that 2 is in the hundreds place.

Since 6 is fourth, that means that 6 is in the thousands place.

Now, we have 8. Since 8 is fifth, that means that 8 is in the ten-thousands place. But that's not the value of the eight. The value of the 8 would be it's place value (10,000) times 8. 10,000 * 8 = 80,000, so the value of the digit 8 in the number 686293 is 80,000.

8 0
3 years ago
Which statements are true regarding the area of circles & sectors? Check all that apply.
Fynjy0 [20]

Answer:

4pi r

Step-by-step explanation:

7 0
2 years ago
1(3/11-7d/17) using distributive property
nadezda [96]
D=51/77
First set up the equation equal to zero(0), the distribute from there.
6 0
2 years ago
What is the approximate volume of a basketball with the circumference of 42ft ?
Semmy [17]
We know that

[volume of a sphere]=(4/3)*pi*r³

length of a circumference=42 ft
[length of a circumference]=2*pi*r-------> r=[length of a circumference]/(2*pi)
r=[42]/(2*pi)---------> r=6.6845 ft

[volume of a sphere]=(4/3)*pi*6.6845³-----------> 1251.11 ft³

the answer is 1251.11 ft³
4 0
3 years ago
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