The temperature was 9 degrees below zero at 11 A.M. By 2 P.M. the temperature had risen 3 degrees. What was the temperature at 2
1 answer:
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Answer:
option b
-3/2
Step-by-step explanation:
Given in the question an expression
ln
First apply logarithm divide rule
= ln1 - ln√e³
ln(1) = 0
so
ln1 - ln√e³ = 0 - ln√e³
-ln√e³ = -ln(e³)^1/2
Apply logarithm power rule
- ln(e³)^1/2 = -lne
-3/2ln(e)
As we know that
ln(e) = 1
so,
-3/2(1)
-3/2