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3 years ago

What is the answer to a milk container's capacity is one gallon how many cups would be equal?

Mathematics

1 answer:

SVETLANKA909090 [29]3 years ago

8 0

1 gallon = 16 cups
it means a milk container's capacity is 16 cups

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Three vertices of a rectangle are located on the coordinate plane shown below. Coordinate plane with points labeled Part A Which

Harlamova29_29 [7]

Answer:

Part A

Which is the ordered pair for Point B?

A. (2, 8)

B. (6, 8)

C. (6, 6)

D. (8, 6)

Part B

Which point is at (8, 2)?

A. A

B. B

C. C

D. None of these

Part C

What are the coordinates of point A?

Enter your answer in the boxes.

(

)

Part D

What are the coordinates of the fourth vertex of the rectangle?

Enter your answer in the boxes.

(

)Step-by-step explanation:

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3 years ago

Find A and B. Using the image above.

NeX [460]

Answer:

a = 7, b = $\frac{7\sqrt{3} }{3}$

Step-by-step explanation:

Using the sine ratio in the left right triangle and the exact value

sin45° = $\frac{1}{\sqrt{2} }$ , then

sin45° = $\frac{opposite}{hypotenuse}$ = $\frac{a}{7\sqrt{2} }$ = $\frac{1}{\sqrt{2} }$ ( cross- multiply )

a × $\sqrt{2}$ = 7 $\sqrt{2}$ ( divide both sides by $\sqrt{2}$ )

a = 7

--------------------------------------------------------

Using the tangent ratio in the right triangle on the right and the exact value

tan60° = $\sqrt{3}$ , then

tan60° = $\frac{opposite}{adjacent}$ = $\frac{a}{b}$ = $\frac{7}{b}$ = $\sqrt{3}$ ( multiply both sides by b )

b × $\sqrt{3}$ = 7 ( divide both sides by $\sqrt{3}$ )

b = $\frac{7}{\sqrt{3} }$ × $\frac{\sqrt{3} }{\sqrt{3} }$ = $\frac{7\sqrt{3} }{3}$

7 0

2 years ago

a store sells 14 2/3 lb of carrots one day. The next day the store sells to 2 1/3 pounds of carrots how many pounds of carrots d

valentinak56 [21]

Answer: 17lbs of carrots

Step-by-step explanation:

8 0

3 years ago

1.8.2

VLD [36.1K]

Answer:

4.66

-0.97

-3/2

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3 0

3 years ago

At an effective annual interest rate of i > 0, each of the following two sets of payments has present value K: (i) A payment

IgorLugansk [536]

Answer:

The present value of K is, $K=251.35$

Step-by-step explanation:

First of all, we need to construct an equation system, so

$(1)K=\frac{169}{(1+i)} +\frac{169}{(1+i)^{2}}$

$(2)K=\frac{225}{(1+i)^{2}} +\frac{225}{(1+i)^{4}}$

Then we equalize both of them so we can find $i$

$(3)\frac{169}{(1+i)} +\frac{169}{(1+i)^{2}}=\frac{225}{(1+i)^{2}} +\frac{225}{(1+i)^{4}}$

To solve it we can multiply $(3)*(1+i)^{4}$ to obtain $(1+i)^{4}*(\frac{169}{(1+i)} +\frac{169}{(1+i)^{2}}=\frac{225}{(1+i)^{2}} +\frac{225}{(1+i)^{4}})$ , then we have $225(1+i)^{2}+225=169(1+i)^{3}+169(1+i)^{2}$ .

This leads to a third-grade polynomial $169i^{3}+451i^{2}+395i-112=0$ , after computing this expression, we find only one real root $i=0.2224$ .

Finally, we replace it in (1) or (2), let's do it in (1) $K=\frac{169}{(1+0.2224)} +\frac{169}{(1+0.2224)^{2}}\\\\K=251.35$

8 0

3 years ago