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3 years ago

A pre-1964 quarter, made

Chemistry

1 answer:

Aleksandr [31]3 years ago

8 0

Answer:

0.595 ml

Explanation:

Mass=Volume*Denisty. Substituting what we know, 6.25=V*10.5. Solving for volume, you will get 0.595 ml.

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The energy produced when nucleons fuse together is called the: Select the correct answer below:

saveliy_v [14]

Answer:

Option C (nuclear binding energy) is the appropriate choice.

Explanation:

At either the nuclear scale, the nuclear binding energy seems to be the energy needed to remove and replace a structure of the atom itself into the characterize elements (to counteract the intense nuclear arsenal).
Nuclear warheads (bargaining power) bind everything together neutrons as well as protons within an elementary particle.

Some other options in question aren't relevant to the particular instance. So that the option preceding will also be the right one.

7 0

3 years ago

Methane, a component in natural gas, can be used as a fuel in combustion reactions. What is the value for ΔGnon (in kJ) for the

Oksanka [162]

<u>Answer:</u> The $\Delta G$ for the reaction is -806.86 kJ

<u>Explanation:</u>

We are given:

$\Delta H^o_{rxn}=-803kJ=-803000J$ (Conversion factor: 1 kJ = 1000)

$\Delta S^o_{rxn}=-4.05J/K$

Temperature of the reaction = 293 K

To calculate the standard Gibbs's free energy of the reaction, we use the equation:

$\Delta G^o_{rxn}=\Delat H^o_{rxn}-T\Delta S^o_{rxn}$

Putting values in above equation, we get:

$\Delta G^o_{rxn}=-803000J-[(293K)\times (-4.05J/K)]=-801813.35J$

For the given chemical equation:

$CH_4(g)+2O_2(g)\rightleftharpoons CO_2(g)+2H_2O(g)$

The expression for $K_c$ is given as:

$K_{c}=\frac{[H_2O]^2[CO_2]}{[CH_4][O_2]^2}$

We are given:

$[H_2O]=6.41M$

$[CO_2]=3.83M$

$[CH_4]=14.51M$

$[O_2]=9.27M$

Putting values in above equation, we get:

$K_c=\frac{(6.41)^2\times 3.83}{14.51\times (9.27)^2}$

$K_c=0.126$

To calculate the Gibbs free energy of the reaction, we use the equation:

$\Delta G=\Delta G^o+RT\ln K_c$

where,

$\Delta G$ = Gibbs' free energy of the reaction = ?

$\Delta G^o$ = Standard gibbs' free energy change of the reaction = -801813.35 J

R = Gas constant = $8.314J/K mol$

T = Temperature = 293 K

$K_c$ = equilibrium constant in terms of concentration = 0.126

Putting values in above equation, we get:

$\Delta G=-801813.35J+(8.314J/K.mol\times 293K\times \ln(0.126))$

$\Delta G=-806859.46J=-806.86kJ$

Hence, the $\Delta G$ for the reaction is -806.86 kJ

8 0

3 years ago

Which structural formula represents an unsaturated hydrocarbon?

bija089 [108]

Answer:

Explanation:

your chosen answer is right as unsaturated mean contains double bond and 1st and 3rd is Wrong as Carbon only can have 4 bonds and 2nd is Wrong as it is saturated.

hope this helps :)

5 0

3 years ago

Calculate the molarity of Kool-Aid if each pack contains 4.5 g of powder, the molar mass of the Kool-aid is 90 g/mol, and it mak

Mandarinka [93]

Answer:

mol mean

Explanation:

sorry

5 0

3 years ago

Perform the following

Eddi Din [679]

11.345
Explanation: 15.225 - 3.880 = 11.345

3 0

3 years ago