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mars1129 [50]
3 years ago
5

A pre-1964 quarter, made

Chemistry
1 answer:
Aleksandr [31]3 years ago
8 0

Answer:

0.595 ml

Explanation:

Mass=Volume*Denisty. Substituting what we know, 6.25=V*10.5. Solving for volume, you will get 0.595 ml.

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Anastaziya [24]
It would be:
2H2 + O2 -> 2H2O


5 0
3 years ago
SOMEONE HELP! With these 2
Setler [38]

Answer: <u><em>THE SECONED ONE</em></u>

Explanation:

7 0
3 years ago
4. A handful of sand has a mass of 208 g and displaces a volume of 80.0 mL. Calculate its
DerKrebs [107]

Answer:

<h2>2.6 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question we have

density =  \frac{208}{80}  = 2.6 \\

We have the final answer as

<h3>2.6 g/mL</h3>

Hope this helps you

7 0
3 years ago
Manuel is heating one liter of water to its boiling point. If one liter of water starts to boil at 100 °C, at what temperature w
Goryan [66]

C im pretty sure because its twice the amount

4 0
3 years ago
54.0 g Al reacts with 64.0 g O2 to
Stells [14]

Answer:

102 g Al₂O₃

Explanation:

To find the mass of Al₂O₃, you need to (1) convert grams Al to moles Al (via molar mass), then (2) convert moles Al to moles Al₂O₃ (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles Al₂O₃ to grams Al₂O₃ (via molar mass). It is important to arrange the ratios in a way that allows for the cancellation of units. The final answer should have 3 sig figs to reflect the given values.

Molar Mass (Al): 26.98 g/mol

Molar Mass (Al₂O₃): 101.96 g/mol

4 Al + 3 O₂ ---> 2 Al₂O₃

54.0 g Al          1 mole             2 moles Al₂O₃         101.96 g
--------------  x  -----------------  x  -----------------------  x  ----------------  =  102 g Al₂O₃
                        26.98 g               4 moles Al            1 mole

4 0
2 years ago
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