Umm. . . Could you list some options? :)
Answer:
This is a basic solution
Explanation:
To be able to provide a succint description of this solution, from the given parameters we can deduce the pH of the solution.
Given parameters:
Concentration of OH⁻ = 1 x 10⁻⁴M
Solution
We knonw that pOH = -log₁₀[OH⁻]
pOH = -log₁₀ 0.0001 = - (-4) = 4
For an aqeous solution:
pH + pOH = 14
pH = 14 - 4 = 10
The pH of the solution has been derieved to be 10
This is a basic solution
Option B. carboxylic acid
For example
CH3 - COOH, is the acetic acid or etanoic acid.
where - COOH is C bonded with O (trhough doble bond) and with OH (with a single bond)
Answer: C
I hope this helped you
