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Debora [2.8K]
3 years ago
11

Rehana has some money after she spend Rs15 she has Three quarter of the initial amount left the amount left is

Mathematics
1 answer:
ludmilkaskok [199]3 years ago
6 0

Answer:

Amount left = Rs 45

Step-by-step explanation:

Let the initial amount be x.

Translating the word problem into an algebraic expression, we have;

x - 15 = \frac {3}{4} * x

x - 15 = \frac {3x}{4}

Cross-multiplying, we have;

4(x - 15) = 3x

4x - 60 = 3x

Rearranging the equation (collecting like terms), we have;

4x - 3x = 60

x = Rs 60

Next, we find the amount left;

Amount left = 60 - 15

Amount left = Rs 45

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mr Goodwill [35]

Answer:

9 x + 8 y = 10   (I)

y = -4x + 7        (II)

One way is to rewrite the second as

4x + y = 7

Now multiply this equation by 8

32 x + 8 y = 56

9 x + 8 y = 10        and now subtract the equations

23 x = 46     this gives x as 2

From equation (II)  y = -4 (2) + 7  = -1

So our values are (2, -1)

Check:

(I) 9 x + 8 y = 10         9 * 2 - 8 = 10

(II)  4 x + y = 7       or 4 * 2 - 1 = 7

Or you can substitute equation (II) directly into equation (I)

3 0
3 years ago
How do I solve this:<br><br>180-(2x-40)<br><br>its a geometry problem.
Anastasy [175]

Answer:

180-1(2x-40)

180-1(2x)+(-1)(-40)

180+−2x+40

Combine Like Terms:

180+−2x+40=(−2x)+(180+40)

-2x+220


Step-by-step explanation:


8 0
4 years ago
According to General Social Survey of 2016, the population distribution of number of years of education for self-employed indivi
nikdorinn [45]

Answer:

a) Mean is 12.9

b) Standard Error

i) n = 16, Standard Error = 1

The shape of the sampling distribution means is not normal

ii) n = 49 , Standard Error = 0.5714285714

The shape of the sampling distribution means is normal

iii) n = 121, Standard Error = 0.3636363636

The shape of the sampling distribution means is normal

c)Describe the pattern as n increases

As the number of random samples(n) increases the value for the standard error decreases

Step-by-step explanation:

Central Limit Theorem states that

if the sample size is large (generally n ≥ 30), and the standard deviation of the population is finite, then the distribution of sample means will be approximately normal.

a) 16 residents

Mean = 12.9

Standard Error = Standard Deviation /√n

= 4/√16

= 4/4

= 1

n < 30, hence, The shape of the sampling distribution means is not normal

b) 49 residents

= Mean = 12.9

Standard Error = Standard Deviation /√n

= 4/√49

= 4/7

= 0.5714285714

n > 30, hence, The shape of the sampling distribution means is normal

c) 121 residents

Mean = 12.9

Standard Error = Standard Deviation /√n

= 4/√121

= 4/11

= 0.3636363636

n > 30, hence, The shape of the sampling distribution means is normal

Describe the pattern as n increases

As the number of random samples(n) increases the value for the standard error decreases

3 0
3 years ago
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Vinil7 [7]

5. yes

6. yes

7. no

8. no

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3 years ago
Find the slop of -1.-1 and 4,-4
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I think it is -1and 4
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