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oksano4ka [1.4K]
3 years ago
13

How to write an expression combining areas of four triangles and two squares

Mathematics
1 answer:
lubasha [3.4K]3 years ago
4 0

Answer:

I don't know

Step-by-step explanation:

I don't know if I get

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lys-0071 [83]

Answer:

yo have to do nothing

Step-by-step explanation:

its 24 by the way

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3 years ago
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How much wrapping paper is needed to cover the gift box shown below?<br> SA = 2Lw + 2Lh + 2wh
Brrunno [24]

Answer:

528 square inches

Step-by-step explanation:

SA = 2(10·16) + 2(10·4) +2(4·16)

= 2(160)+2(40)+2(64)

= 320 + 80 + 128

= 528 square inches

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Brenda is planning her birthday party. She wants to have 10.82 liters of punch, 6.5 gallons of ice cream 3.9 pounds of fudge and
faltersainse [42]

The answer is 0.4328 liters hope this helped!


6 0
3 years ago
60 is 40 percent of what number
nydimaria [60]
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3 years ago
Please show your work this question what made you come to the conclusion. Thank you
AveGali [126]

Answer:

B the range, the x- and y-intercept

Step-by-step explanation:

the domain stays the same : all values of x are possible out of the interval (-infinity, +infinity).

but the range changes, as for the original function y could only have positive values - even for negative x.

the new function has a first term (with b) that can get very small for negative x, and then a subtraction of 2 makes the result negative.

the y-intercept (x=0) of the original function is simply y=1, as b⁰=1.

the y-intercept of the new function is definitely different, because the first term 3×(b¹) is larger than 3, because b is larger than 1. and a subtraction of 2 leads to a result larger than 1, which is different to 1.

the original function has no x-intercept (y=0), as this would happen only for x = -infinity. and that is not a valid value.

the new function has an x-intercept, because the y-values (range) go from negative to positive numbers. any continuous function like this must therefore have an x-intercept (again, y = the function result = 0)

3 {b}^{x + 1}  = 2

{b}^{x + 1}  = 2 \div 3

log_{b}(2 \div 3)  = x + 1

x =  log_{b}(2 \div 3)  - 1

8 0
3 years ago
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