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kirill115 [55]
3 years ago
8

List the integers that satisfy both these inequalities. Put the answers on one line.

Mathematics
1 answer:
bekas [8.4K]3 years ago
6 0

Answer:

-7, -6, -5, -4, -3

Step-by-step explanation:

Given:

2x + 5 < 0

x > -8

Thus, we can combine both statements to find out integers that satisfy both inequalities.

2x + 5 < 0

Let's find x

2x < 0 - 5 (substraction property)

2x < -5

Divide both sides by 2

x < -5/2

This implies that -5/2 is greater than the set of values of x.

The second inequality, x > -8 implies that -8 is less than the value of x.

Les combine both:

-8 < x < -5/2

Therefore, the possible set of integers are whole numbers between the range of -8 and -5/2 which excludes -8 and -5/2.

Thus, they are:

-7, -6, -5, -4, -3

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1 year ago
1.
vodka [1.7K]

9514 1404 393

Answer:

  C.  The zeros are -1 and 5/2, because f(x) = (x + 1)(2x-5).

Step-by-step explanation:

The zeros of the function are the values that make the factors zero. The factors need to multiply out to give the original standard-form equation.

The sign of the constant (-5) tells you the product of the constants in the factors must be -5. That is only true for choices B and C.

Additionally, the x-term needs to match the result of multiplying out the factors.

  B.  (x -1)(2x +5) = 2x^2 +3x -5 . . . . . . . . . wrong x-term (not -3x)

  C.  (x +1)(2x -5) = 2x^2 -3x -5 . . . . . . . . . matches the given f(x)

The factors of C are zero when x=-1, x=5/2.

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