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Gre4nikov [31]
4 years ago
7

People start to leave the stadium at the end of a football game. The number of people, PPP, that are left in the stadium mmm min

utes after the end of the game is given by the equation above. How many people were present when the game ended but before people started to leave? P=45,000−1,000m
Mathematics
1 answer:
vitfil [10]4 years ago
7 0

Answer:

45,000

Step-by-step explanation:

If P=45,000−1,000m,

where P=The number of people left in the stadium m minutes after the end of the game

We want to determine how many people were present when the game ended but before people started to leave.

Note that immediately the game ended,

m=0

Therefore, the number of people left in the stadium

P=45000−(1000 X 0)

P=45000

There were 45,000 people.

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WARRIOR [948]

Answer: a= 144. b= 67

Step-by-step explanation:

Angle b and the angle of measure 113 are same side interior angles which sum to 180 (When 2 parallel lines are cut by a transversal, special angles are formed)

113+b=180. Subtract 113 from both sides.

b= 67 degrees

Now that you have b, the interior angles of four sided figures sum to 360.

a+113+67+36=360. Combine like terms.

a+216=360. Subtract 216 from both sides.

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3 years ago
Please answer! I’ll give you Brainliest
Sergio [31]

A)

The four small squares are all 3x3, so the perimeter is 3+3+3+3 = 12.

12 * 4 = 48

We can find the perimeter of the large diamond shape using the Pythagorean theorem, a^2 + b^2 = c^2

a = 4

b = 4

4^2 + 4^2 = c^2

16 + 16 = c^2

32 = c^2

c = 5.65685425

So the perimeter of the large diamond shape is

5.65685425+5.65685425+5.65685425+5.65685425 = 22.627417

48+22.6 = 70.6

B)

The areas of the small squares are 3x3 = 9

9 * 4 = 36

The area of the large diamond shape is

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2 years ago
A machine makes 18 parts per hour if the machine work for 24 hourss how many parts will it have made
sweet-ann [11.9K]

Answer:

432 parts

Step-by-step explanation:

24 x 18 = 432

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2 years ago
Rewa Delta Union Rugby CEO has become concerned about the slow pace of the rugby games played in the current union rugby, fearin
ozzi

Answer:

We conclude that the mean duration of 15-sided union rugby games has decreased after the meeting.

Step-by-step explanation:

We are given that Before the meeting, the mean duration of the 15-sided rugby game time was 3 hours, 5 minutes, that is, 185 minutes.

A random sample of 36 of the 15-sided rugby games after the meeting showed a mean of 179 minutes with a standard deviation of 12 minutes.

Let \mu = <em><u>mean duration of 15-sided union rugby games after the meeting.</u></em>

So, Null Hypothesis, H_0 : \mu \geq 185 minutes      {means that the mean duration of 15-sided union rugby games has increased or remained same after the meeting}

Alternate Hypothesis, H_A : \mu < 185 minutes     {means that the mean duration of 15-sided union rugby games has decreased after the meeting}

The test statistics that would be used here <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

                            T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean duration of 15-sided union rugby games = 179 min

            s = sample standard deviation = 12 minutes

            n = sample of 15-sided rugby games = 36

So, <u><em>the test statistics</em></u>  =  \frac{179-185}{\frac{12}{\sqrt{36} } }  ~ t_3_5

                                       =  -3

The value of t test statistics is -3.

<u>Now, at 1% significance level the t table gives critical value of -2.437 at 35 degree of freedom for left-tailed test.</u>

Since our test statistic is less than the critical value of t as -3 < -2.437, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that the mean duration of 15-sided union rugby games has decreased after the meeting.

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