Somebody please help and explain it.

Mathematics

1 answer:

s2008m [1.1K]3 years ago

3 0

Explanation is in the file

tinyurl.com/wpazsebu

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Solve for x in simplest form. 3=7/2(3x−4)

polet [3.4K]

Answer:

x = 34/21

Step-by-step explanation:

3 = 7/2 (3x-4)
3 = (21/2)x - 28/2
3 = (21/2)x - 14
(21/2)x = 17
21x = 34
x = 34/21

6 0

2 years ago

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I dont k ow what to do on this problem 0.8/71.73

Taya2010 [7]

0.8 divided by 71.73 = 0.01115293461

7 0

3 years ago

I NEED A LITTLE HELP WITH MATH PLZ

Paraphin [41]

Hi there!

Amit's estimate would be a close estimate!

If you add the fractions together and put it in decimal form you get 4.96 which is very close to Amit's estimate of 5.

8 0

3 years ago

Solve y= 2x^2 + 4x + 1 by quadratic factoring

ollegr [7]

Solve the rational equation by combining expressions and isolating the variable y (solve for y). So, nothing further can be done with this topic:

Answer: y=2x^2+4x+1

5 0

3 years ago

At time t = 0 a car has a velocity of 16 m/s. It slows down with an acceleration given by –0.50t, in m/s^2 for t in seconds. By

anygoal [31]

The car's velocity at time $t$ is

$v(t)=16\dfrac{\rm m}{\rm s}+\displaystyle\int_0^t\left(\left(-0.50\frac{\rm m}{\mathrm s^2}\right)u\right)\,\mathrm du=16\dfrac{\rm m}{\rm s}+\left(-0.25\dfrac{\rm m}{\mathrm s^2}\right)t^2$

It comes to rest at

$v(t)=0\implies16\dfrac{\rm m}{\rm s}=\left(0.25\dfrac{\rm m}{\mathrm s^2}\right)t^2\implies t=8.0\,\mathrm s$

Its velocity over this period is positive, so that the total distance the car travels is

$\displaystyle\int_0^{8.0}v(t)\,\mathrm dt=\left(16\dfrac{\rm m}{\rm s}\right)(8.0\,\mathrm s)+\frac13\left(-0.25\dfrac{\rm m}{\mathrm s^2}\right)(8.0\,\mathrm s)^3=\boxed{85\,\mathrm m}$

so the answer is D.

4 0

2 years ago