I'm pretty sure the attachment down there can answer ur question! :D
Numerator = -3( - 8) = - 3 - 8 = -11
Denominator = 5 + 7 = 12
So the quotient = -11/12
Answer
- 11/12
The probability that the transistor will last between 12 and 24 weeks is 0.424
X= lifetime of the transistor in weeks E(X)= 24 weeks
O,= 12 weeks
The anticipated value, variance, and distribution of the random variable X were all provided to us. Finding the parameters alpha and beta is necessary before we can discover the solutions to the difficulties.
X~gamma(
)
E(X)=
=
=6 weeks
V(x)=
=24/6= 4
Now we can find the solutions:
The excel formula used to create Figure one is as follows:
=gammadist(X,
,
, False)
P(
)
P(
)
P(
)
P= 0.424
Therefore, probability that the transistor will last between 12 and 24 weeks is 0.424
To learn more about probability click here:
brainly.com/question/11234923
#SPJ4
Answer:x^2−y^2+4x−6y−5
Step-by-step explanation:
(24*32)/(2*3)
(768)/(6)
=128
I hope this helped you!!