The correct answer is p/rs.
In order to find this first state the direct variation with the constant k included.
p = krs
Now to find the value of k, we simply divide away the r and s
p/rs = k
ΔADC ≅ ΔBCD (SAS congruency)
∠AED ≅ ∠BEC (opposite angles)
ΔAED ≅ ΔBEC (ASA congruency)
Therefore DE <span>≅ CE (corresponding sides of the two congruent triangles AED and BEC)</span>
Answer:
1. DF (option 3)
2. segment addition postulate
3. segment congruence postulate
4. DF (option 5)
