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valkas [14]
3 years ago
7

The labels on a shipment of the five chemicals A –E below were washed off by accident when the delivery truck went through a tru

ckwash with the doors open. A clever student took infrared spectra of each of the resulting unknowns. Unknown #1 had a strong, broad IR absorption at 3400–3600 cm–1, and no absorptions between 1600 and 2900 cm–1. Unknown #2 had a strong absorption at 1680 cm–1 and no absorptions above 3100 cm–1. What are the structures of unknowns 1 and 2?
Mathematics
1 answer:
Tanya [424]3 years ago
8 0

Answer:

Unknown 1: -OH group at 3400-3600

Unknown 2: Ketone and alkene group

Step-by-step explanation:

Unknown 1:

This compound has a strong IR absorption at 3400 - 3600cm-¹; this indicates that it is an alcoholic group (OH)

No absorption between 1600 and 2900cm-¹: this rule out the presence of ketone (C = O)

Hence the unknown compound is OH group

Unknown 2:

This has strong IR absorption at 1680cm-¹: this indicates the presence of (C=O) group.

No absorptions above 3100cm-¹: this indicates the presence of C = C - H

So therefore, unknown 2 is most likely to be Ketone and alkene group

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Due to a packaging error, 4 cans labeled diet soda were accidentally filled with regular soda and placed in a 12 pack carton of
Sophie [7]

Answer:

Probability that both cans were regular soda =  \frac{1}{11}

Step-by-step explanation:

Probability = \frac{Desired outcome}{Total possible outcomes}

We are given 12 total number of cans; 4 cans have been accidentally filled with diet soda.

Probability that first can is a regular soda:

Outcome that first can is a regular soda will give us the number of regular soda available which are 4

Using formula of probability

Total possible outcomes are, n(total) = 12

Desired outcome: 4 (cans of regular soda)

P(1st can) =  \frac{4}{12} = \frac{1}{3}

Probability that 2nd can is a regular soda:

<em>As we have already taken a can of regular soda from the pack, the total soda in the pack now 11 and the regular soda left are 3.</em>

Total possible outcomes are, n(total) = 11

Desired outcome: 3 (cans of regular soda as one has already been taken)

P(2nd can) =  \frac{3}{11}


Probability that both cans are regular soda:

P(both) = P(1st can) × P(2nd can)

             = \frac{1}{3} * \frac{3}{11}

             = \frac{1}{11}

3 0
3 years ago
Read 2 more answers
In every bar graph , line graph , or scatter plot , the vertical axis should include the following
alexgriva [62]
It should include zero
8 0
3 years ago
30 points if I had 125 quarter how much money I would have
inna [77]

Answer:

$31.25

Step-by-step explanation:

125 divided by 4 = 31.25

$31.25

4 0
2 years ago
Read 2 more answers
You have $83 in your bank account each week you plan to deposit eight dollars from your allowance and $15 from your paycheck the
docker41 [41]
We know that you have 83$ in your bank account.

Okay so what is 15+8=23 So that means you get 23$ per week.

Now what is 83+23=106
106+23=129
129+23=152
152+23=175
Now that was four 23's


That means it would take 4 weeks for you to have 175 dollars in your bank account.
Hope this helped.
7 0
3 years ago
Question 8 of 10
Andreyy89

Median and IQR are the most appropriate measures of center and spread for this data set.

<h3>Why are Median and IQR the most appropriate?</h3>

Among the 3 central tendencies that includes the mean, median and mode; the median is the better measure because of the followings:

  • Mean is affected by extreme values
  • Mean is not correct if more outliers are present
  • Mean may not represent the nature of the data whether skewed right or left.

Also, the median as the middle entry is not affected by extreme items or outliers, so the median is better than mean,

Furthermore, for the measure of spread, the IQR is better since extreme items will show higher std deviation and also some outliers mislead.

Therefore, Option B is correct.

Read more about measures of center

brainly.com/question/10610456

#SPJ1

5 0
2 years ago
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