Answer: ![\begin{bmatrix}\mathrm{Solution:}\:&\:x\le \frac{17}{3}\:\\ \:\mathrm{Decimal:}&\:x\le \:5.66666\dots \\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:\frac{17}{3}]\end{bmatrix}](https://tex.z-dn.net/?f=%5Cbegin%7Bbmatrix%7D%5Cmathrm%7BSolution%3A%7D%5C%3A%26%5C%3Ax%5Cle%20%5Cfrac%7B17%7D%7B3%7D%5C%3A%5C%5C%20%5C%3A%5Cmathrm%7BDecimal%3A%7D%26%5C%3Ax%5Cle%20%5C%3A5.66666%5Cdots%20%5C%5C%20%5C%3A%5Cmathrm%7BInterval%5C%3ANotation%3A%7D%26%5C%3A%28-%5Cinfty%20%5C%3A%2C%5C%3A%5Cfrac%7B17%7D%7B3%7D%5D%5Cend%7Bbmatrix%7D)
Step-by-step explanation:
Answer:
(a). $35746. (b). Higher.
Step-by-step explanation:
(a). Given that the least-squares regression equation is y = 7163x + 14242. Also, in the question above we are given that y is the median income and x is the percentage of 25 years and older with at least a bachelor's degree in the region, that is to say that the value of x = 30.
Therefore, y = 7163x + 14242.
y = (7163 × 30) + 14242.
y = $35746.
(b). The condition for our x is; 28.7 percent of adults 25 years and older have at least a bachelor's degree.
Then, y = (7163 × 28.7) + 14242.
y = $34814.
Hence, we have the median income in this region = $38,163 HIGHER than $34814.
Answer:
(98/100)*110 = $107.8
Step-by-step explanation:
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