All categories

3 years ago

What is m<1 and m<2 A 40 B 50 C 140 D 90

Mathematics

1 answer:

lina2011 [118]3 years ago

3 0

Answer:

<h2>here...... </h2><h2>m′<1 = 40°</h2><h2>and</h2><h2> m'<2= 20°</h2><h2>------++++--------</h2><h2>sum of angle of triangle is 180°</h2>

You might be interested in

V(t)=t2−3t what is the meaning of the quantity v(4) ?

GalinKa [24]

V(4)=4²-3×4=16-12=4 is the result of substituting t=4 in the function.

5 0

3 years ago

Please I really need help I’m in a test right now plssss guys

laiz [17]

Answer:

12x + 50

Y - intercept = 50

Slope = 12

Step-by-step explanation:

The y - intercept represents the original registrational fee even if you have never taken lessons.

The slope represents what you have to pay every time you take a lesson.

6 0

3 years ago

How is constructing an angle bisector similar to constructing a perpendicular bisector?

Sophie [7]

Hello,
Your answer would be D.

4 0

3 years ago

Prove that {(tanθ+sinθ)^2-(tanθ-sinθ)^2}^2 =16(tanθ+sinθ)(tanθ-sinθ)

USPshnik [31]

First, expand the terms inside the bracket you will get

$(( \tan {}^{2} (x) + 2 \tan(x) \sin(x) + \sin {}^{2} (x) - ( \tan {}^{2} (x) - 2 \tan(x) + \sin {}^{2} (x) ) {}^{2} = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$( 4 \tan(x) \sin(x) ) {}^{2} = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$16 \tan {}^{2} (x) \sin {}^{2} (x) = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$16 \tan {}^{2} (x) (1 - \cos {}^{2} (x) ) = 16 (\tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$16( \tan {}^{2} (x) - \frac{ \sin {}^{2} (x) \cos {}^{2} ( {x}^{} ) }{ \cos {}^{2} (x) }$

$16( \tan {}^{2} (x) - \sin {}^{2} (x) ) = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

5 0

2 years ago

(-8)–(-13)? Answer plz

Mademuasel [1]

Answer:

Step-by-step explanation:

(-8)-(-13)= 5

8 0

2 years ago

Read 2 more answers