Answer:
2.9
Step-by-step explanation:
It just is
I think it would be 10,200
Answer:
(- 1, 2)
Step-by-step explanation:
Given a quadratic in standard form y = ax² + bx + c : a ≠ 0
Then the x- coordinate of the vertex is
= - 
f(x) = x² + 2x + 3 ← is in standard form
with a = 1 and b = 2, hence
= -
= - 1
Substitute x = - 1 into f(x) for corresponding value of y
f(- 1) = (- 1)² + 2(- 1) + 3 = 1 - 2 + 3 = 2
vertex = (- 1, 2 )
Find the x and y-intercepts of the equation. Then calculate the points at constant intervals and plot and connect those points on a makeshift graph. A quadratic equation can have 2 solutions, 1 solution, or none. The corresponding graphs(if two solutions) would most probably cross over the x-axis twice.
Hope this helps.