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andrey2020 [161]
3 years ago
14

Find a b if a = 4/3 and b = 4/5

Mathematics
1 answer:
Wewaii [24]3 years ago
8 0

Answer: b is 5/4

Step-by-step explanation:

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The length of a rectangular piece of land is 9 cm more than 3 times its width. The perimeter is 418 cm. Find its dimensions.
SashulF [63]

Let w represent the width of the rectangle in cm. Then its length in cm is (3w+9). The perimeter is the sum of two lengths and two widths, so is ...

... 418 = 2(w + (3w+9))

... 209 = 4w +9 . . . . . . divide by 2, collect terms

... 200 = 4w . . . . . . . . subtract 9

... 50 = w . . . . . . . . . . divide by 4

... length = 3w+9 = 3·50 +9 = 159

The dimensions of this piece of land are 159 cm by 50 cm.

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3 years ago
Help? with complete solution​ please help me please
serious [3.7K]

9514 1404 393

Answer:

  1. 13 ft
  2. (a) 1 second; (b) t = 0, t = 1/2

Step-by-step explanation:

<h3>1. </h3>

Let w represent the length of the wire. Then the height of attachment is (w-1). The Pythagorean theorem tells us a relevant relation is ...

  5² +(w -1)² = w²

  w² -2w +26 = w² . . . . . . . eliminate parentheses, collect terms

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  13 = w . . . . . . . . . . . . divide by 2

The length of the wire is 13 feet.

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(a) When h = 0, the equation is ...

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Dividing by -8 puts this into standard form:

  2t^2 -t -1 = 0

Factoring, we get ...

  (2t +1)(t -1) = 0

The positive value of t that makes a factor zero is t = 1.

It will take 1 second for the gymnast to reach the ground.

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(b) When h = 8, the equation is ...

  8 = -16t^2 +8t +8

Subtract 8 and divide by 8 to get ...

  0 = -2t^2 +t

  0 = t(1 -2t) . . . . factor out t

Values of t that make the factors zero are ...

  t = 0

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The gymnast will be 8 feet above the ground at the start of the dismount, and 1/2 second later.

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2 years ago
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There are infinity of fractions equal to 1/2, it just means half of a number, so for example, 3/6, 4/8, 5/10, 6/12 are all equal to 1/2 and so on
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(40 PTS HELP)Which ordered pair makes both inequalities true?
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(1, 2) i think sorry
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Velocity = change in speed/change in time

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