Find a b if a = 4/3 and b = 4/5

Mathematics

1 answer:

Wewaii [24]2 years ago

8 0

Answer: b is 5/4

Step-by-step explanation:

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What is the solution to the equation -3d/a^2-2d-8 + 3/d-4 = -2/ d+2

Alex73 [517]

Answer:

d=1

Step-by-step explanation:

$\frac{-3d}{d^2-2d-8} +\frac{3}{d-4} =\frac{-2}{d+2}$

Lets factor the denominator d^2 -2d-8

d^2 - 2d - 8 = (d-4)(d+2)

$\frac{-3d}{(d-4)(d+2)} +\frac{3}{d-4} =\frac{-2}{d+2}$

Now make the denominators same

LCD: (d-4)(d+2)

$\frac{-3d}{(d-4)(d+2)} +\frac{3(d+2)}{(d-4)(d+2)} =\frac{-2(d-4)}{(d+2)(d-4)}$

Denominators are same on both sides

So equate the numerators

-3d +3(d+2) = -2(d-4)

-3d +3d +6 = -2d +8

6 = -2d + 8

subtract 8 on both sides

-2 = -2d

So d=1

3 0

2 years ago

Read 2 more answers

Find the distance between the following points using the Pythagorean theorem: (-5, 4) and (8, -3)

3241004551 [841]

First, draw a diagram to visualize the situation:

As we can see, the difference between the x-coordinates of the points is the length of one leg of a right triangle, and the difference between the y-coordinates is the length of the other leg.

Then, for the given points (-5,4) and (8,-3), the distance given by the Pythagorean Theorem is:

$\begin{gathered} d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\ \\ =\sqrt{(8--5)^2+(-3-4)^2} \\ \\ =\sqrt{(13)^2+(-7)^2} \\ \\ =\sqrt{169+49} \\ \\ =\sqrt{218} \\ \\ \approx14.7648... \end{gathered}$

Therefore, the distance between the points (-5,4) and (8,-3) is: √218.