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photoshop1234 [79]
2 years ago
13

Solve for x. Assume that lines which appear to be diameters are actual diameters.​

Mathematics
1 answer:
Natalija [7]2 years ago
3 0

Answer:

Answer is B) -11

Step-by-step explanation:

x + 161 + 131 + 79 = 360°

x + 371 = 360

x = 360 - 371

x = -11

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A pack of folders has a length of 5 inches, a width of 12 inches, and a height of 1 inch. The pack of folders will be shipped in
777dan777 [17]

Answer:

A) Each pack of folders has a volume of 60 cubic inches.

B) The box has a volume of about 720 cubic inches

D) If the box help 20 packs of folders, it would have a volume of about 1,200 cubic inches.

Step-by-step explanation:

<em><u>Verify each statement</u></em>

<em>A) Each pack of folders has a volume of 60 cubic inches.</em>

The statement is True

Because

The volume of each pack of folders is equal to

V=(5)(12)(1)=60\ in^{3}

<em>B) The box has a volume of about 720 cubic inches</em>

The statement is True

Because

The volume of the box is equal to the volume  of one pack of folders multiplied by 12

so

V=(12)60=720\ in^{3}

<em>C) If the box held 15 packs of folders, it would have a volume of about 1,200 cubic inches</em>

The statement is False

Because

Applying proportion

\frac{12}{720}\frac{packs}{in^{3}}=\frac{15}{x}\frac{packs}{in^{3}}\\ \\x=720*15/12\\ \\x=900\ in^{3}

900\ in^{3}\neq 1,200\ in^{3}

<em>D) If the box help 20 packs of folders, it would have a volume of about 1,200 cubic inches.</em>

The statement is True

Because

Applying proportion

\frac{12}{720}\frac{packs}{in^{3}}=\frac{20}{x}\frac{packs}{in^{3}}\\ \\x=720*20/12\\ \\x=1,200\ in^{3}

1,200\ in^{3}= 1,200\ in^{3}

<em>E) Each pack of folders has a volume of 24 cubic inches.</em>

The statement is False

Because

The volume of each pack of folders is equal to

V=(5)(12)(1)=60\ in^{3}

7 0
3 years ago
What’s the answer for -3(r-4)_&gt;0
Zigmanuir [339]

Answer:

r<4

Step-by-step explanation:

-3(r-4)>0 step 1: distribute the -3

-3r+12>0  explain: -3 times r =-3r, -3 times -4 = 12

next, isolate the -3r by putting 12 on the other side

-3r+12>0    subtract 12 from both sides

-3r>-12    now, divide both sides by -3    (you have to flip the > because you are dividing by a negative) -12 divided by -3 is 4

so you should end up with r<4

8 0
3 years ago
What is the slope Of a line that passes through the points (9,8) and (2,3)?
tresset_1 [31]

(\stackrel{x_1}{9}~,~\stackrel{y_1}{8})\qquad (\stackrel{x_2}{2}~,~\stackrel{y_2}{3}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{3}-\stackrel{y1}{8}}}{\underset{run} {\underset{x_2}{2}-\underset{x_1}{9}}}\implies \cfrac{-5}{-7}\implies \cfrac{5}{7}

6 0
2 years ago
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3 years ago
What is 195 squared to the nearest integer
densk [106]
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