Can anyone please help with this for brainliest?

carlos can write 3 to 4 pages in his journal in 2/3 hour. if he writes for 5 hours, what's a reasonable number of pages he can w

zheka24 [161]

Answer:

23, 24, 25, 26, 27, 28, 29, or 30

22.5 ≤ p ≤ 30

Step-by-step explanation:

So we know that in 2/3 hours, Carlos can write 3 to 4 pages.

First, lets find how many 2/3's are in 5. Lets divide 5 by 2/3.

$\frac{5}{\frac{2}{3}}=7.5$

So there are 7.5 2/3's in 5.

Now, lets assume Carlos writes 4 pages per 2/3 hours consistently throughout that 5 hours. This would yield the maximum amount of pages Carlos can write in 5 hours.

7.5(4) = 30

So the maximum amount of pages Carlos can write in 5 hours is 30.

Now, lets assume Carlos writes 3 pages per 2/3 hours consistently throughout that 5 hours. This would yield the minimum amount of pages Carlos can write in 5 hours.

7.5(3) = 22.5

So the minimum amount of pages Carlos can write in 5 hours is 22.5.

Now we can write the information that we found as an inequality. Lets make p equal to the pages that Carlos can write in 5 hours.

22.5 ≤ p ≤ 30

Any value greater than to equal to 22.5 and less than or equal to 30 would be reasonable.

I hope you find my answer and explanation to be helpful. Happy studying.

8 0

3 years ago

Estimate round to nearest ten thousand 649,891 - 35,427

Setler [38]

694,891 - 35,427 rounded to the nearest ten thousand is 614,000.

6 0

3 years ago

Under federalism who was directly responsible for protecting the people

Alex Ar [27]

Answer: The knights were responsible for protecting the people.

6 0

3 years ago

A data mining routine has been applied to a transaction dataset and has classified 88 records as fraudulent (30 correctly so) an

chubhunter [2.5K]

Answer:

The classification matrix is attached below

Part a

The classification error rate for the records those are truly fraudulent is 65.91%.

Part b

The classification error rate for records that are truly non-fraudulent is 96.64%

Step-by-step explanation:

The classification matrix is obtained as shown below:

The transaction dataset has 30 fraudulent correctly classified records out of 88 records, that is, 30 records are correctly predicted given that an instance is negative.

Also, there would be 88 - 30 = 58 non-fraudulent incorrectly classified records, that is, 58 records are incorrectly predicted given that an instance is positive.

The transaction dataset has 920 non-fraudulent correctly classified records out of 952 records, that is, 920 records are correctly predicted given that an instance is positive.

Also, there would be 952 - 920 = 32 fraudulent incorrectly classified records, that is, 32 records incorrectly predicted given that an instance is negative.

That is,

Predicted value

Active value Fraudulent Non-fraudulent

Fraudlent 30 58

non-fraudulent 32 920

The classification matrix is obtained by using the information related to the transaction data, which is classified into fraudulent records and non-fraudulent records.

The error rate is obtained as shown below:

The error rate is obtained by taking the ratio of $\left( {b + c} \right)(b+c)$ and the total number of records.

The classification matrix is, shown above

The total number of records is, $30 + 58 + 32 + 920 = 1,040$

The error rate is,

$\begin{array}{c}\\{\rm{Error}}\,{\rm{rate}} = \frac{{b + c}}{{{\rm{Total}}}}\\\\ = \frac{{58 + 32}}{{1,040}}\\\\ = \frac{{90}}{{1,040}}\\\\ = 0.0865\\\end{array}$

The percentage is $0.0865 \times 100 = 8.65$

(a)

The classification error rate for the records those are truly fraudulent is obtained by taking the rate ratio of b and $\left( {a + b} \right)(a+b)$ .

The classification error rate for the records those are truly fraudulent is obtained as shown below:

The classification matrix is, shown above and in the attachment

The error rate for truly fraudulent is,

$\begin{array}{c}\\FP = \frac{b}{{a + b}}\\\\ = \frac{{58}}{{30 + 58}}\\\\ = \frac{{58}}{{88}}\\\\ = 0.6591\\\end{array}$

The percentage is, $0.6591 \times 100 = 65.91$

(b)

The classification error rate for records that are truly non-fraudulent is obtained by taking the ratio of d and $\left( {c + d} \right)(c+d)$ .

The classification error rate for records that are truly non-fraudulent is obtained as shown below:

The classification matrix is, shown in the attachment

The error rate for truly non-fraudulent is,

$\begin{array}{c}\\TP = \frac{d}{{c + d}}\\\\ = \frac{{920}}{{32 + 920}}\\\\ = \frac{{920}}{{952}}\\\\ = 0.9664\\\end{array}$

The percentage is, $0.9664 \times 100 = 96.64$

8 0

3 years ago

Y is inversely proportional to V1+x.<br> When x = 8, y = 2.<br> Find y when x = 15.

murzikaleks [220]

Answer:

y = 1.5

Step-by-step explanation:

Given x is inversely proportional to $\sqrt{1+x}$ , then the equation relating them is

y = $\frac{k}{\sqrt{1+x} }$ ← k is the constant of proportion

To find k use the condition when x = 8, y = 2

2 = $\frac{k}{\sqrt{1+8} }$ = $\frac{k}{\sqrt{9} }$ = $\frac{k}{3}$ ( multiply both sides by 3 )

6 = k

y = $\frac{6}{\sqrt{1+x} }$ ← equation of proportion

When x = 15 , then

y = $\frac{6}{\sqrt{1+15} }$ = $\frac{6}{\sqrt{16} }$ = $\frac{6}{4}$ = $\frac{3}{2}$ = 1.5

6 0

3 years ago