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3 years ago

Is this rational or irrational?

Mathematics

1 answer:

erica [24]3 years ago

6 0

Answer:

rational

hope it helps.

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A simple random sample of size n equals 200 individuals who are currently employed is asked if they work at home at least once p

____ [38]

Answer: 99% of confidence interval for the population proportion of employed individuals who work at home at-least once per week

//0.20113,0.20887[/tex]

Step-by-step explanation:

step 1:-

Given sample size n=200

of the 200 employed individuals surveyed 41 responded that they did work at home at least once per week

Population proportion of employed individuals who work at home at least once per week P = $\frac{x}{n} =\frac{41}{200} =0.205$

Q=1-P= 1-0.205 = 0.705

step 2:-

Now $\sqrt{\frac{P Q}{n} } =\sqrt{\frac{(0.205)(0.705)}{200} }$

=0.0015

step 3:-

Confidence intervals

using formula

$(P - Z_∝} \sqrt{\frac{P Q}{n},} (P + Z_∝} \sqrt{\frac{P Q}{n},$

$(0.205-2.58(0.0015),0.205+2.58(0.0015)\\0.20113,0.20887$

=0.20113,0.20887[/tex]

conclusion:-

99% of confidence interval for the population proportion of employed individuals who work at home at-least once per week

//0.20113,0.20887[/tex]

4 0

3 years ago

HELP ME PLEASE PLEASE

-BARSIC- [3]

Answer:6=C 7=C

Step-by-step explanation:

5 0

3 years ago

What does m2+ m3= ???????????

zimovet [89]

Answer:

M2+m3=90

Step-by-step explanation:

Angle 1 already is equal to 90. A triangle can only go up to 180 wo the other two angles have to add up to 90.

8 0

3 years ago

Prove that triangle with side lengths of x^2-1, 2x, x^2+1 is a right triangle.

Brrunno [24]

Right triangles must follow the pythagorean theorem, so a^2+b^2=c^2.

Let's find a^2 and b^2 by squaring the first 2 side lengths.

(x^2-1)^2= x^4-2x^2+1
(2x)^2= 4x^2

Then add the two to find c^2
x^4+ 2x^2 +1= c^2

Root both sides
x^2+1=c

Since the side lengths can be plugged into the pythagorean theorem, the side lengths must represent a right triangle.
Hope this helps!

7 0

3 years ago

Each child ticket for a ride cost $3 each adult ticket cost $5 if the ride collected a total of $150 and 40 tickets were sold ho

Tcecarenko [31]

25 tickes of child and 15 tickets adult.

4 0

3 years ago