PLEASE HELP ASAP!!!!!!

What’s x-b divided by a= c.. for b

aivan3 [116]

$x-b:a=c\qquad|-x\\\\-\dfrac{b}{a}=c-x\qquad|\cdot(-a)\\\\b=-a(c-x)\\\\b=-ac-a(-x)\\\\\boxed{b=ax-ac}$

3 0

3 years ago

I need help please. How do I find the value of x?

Zina [86]

X = 58

The angle directly across from the 32 is also 32 degrees because it uses the same lines at the same angles. That's the Vertical Angles Theorem. The line straight across means that is 180 degrees, which is already split in half by the visible 90 degree angle (given by the box in the corner). Since all the angles are on the same side of the line, the 180 degree angle, they should add up to equal 180 degrees. Also, since 90 is half of 180, the 32 degree angle and the x angle should just add up to equal 90 degrees. So, 90 minus 32 equals 58.

7 0

3 years ago

Critical Thinking: Empirical/Quantitative Skills

aliya0001 [1]

Answer:

1. 0.0910 = 9.10% probability that exactly 180 passengers show up for the flight.

2. 0.4522 = 45.22% probability that at most 180 passengers show up for the flight.

3. 0.5478 = 54.78% probability that more than 180 passengers show up for the flight.

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .