The dimensions of the school yard is 58 m and 89 m.
<h3>What is rectangle ?</h3>
A rectangle is a polygon with four sides , It has opposite sides parallel and equal.
It is given that
A rectangular school yard has a perimeter of 294 meters
Perimeter of a rectangle is given by
P = 2(Length +Breadth)
294 = 2( L+B)
147 = L+B
Area of a rectangle is given by
L*B = 5162
B = 5162/L
L + 5162/L =147
L² -147L +5162 = 0
L² -58L - 89L+5162 = 0
L(L-58) -89(L-58)
L = 58 , 89
The dimensions of the school yard is 58 m and 89 m.
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Answer:
The volume of the stones is 382 cube inches.
Step-by-step explanation:
The dimensions of the aquarium are;
length = 16 inches
width = 8 inches
height = 10 inches
The height of the water in the aquarium = 4 inches
i. Volume of the water in the aquarium = length x width x height
= 16 x 8 x 4
= 512 cube inches
The volume of water in the aquarium is 512 cube inches.
ii. The new height of water = 7 inches.
New volume of water = 16 x 8 x 7
= 896 cube inches
The new volume of water is 869 cube inches.
The volume of the stones = New volume of water - initial volume of water
= 869 - 512
= 384 cube inches
The volume of the stones is 382 cube inches.
Answer:
Value of b = 14
Step-by-step explanation:
The detailed calculations with steps is shown in the attachment.
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