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exis [7]
3 years ago
15

26-(6y-10)=27y-18-37 First will get brainliest!

Mathematics
1 answer:
stepan [7]3 years ago
8 0

Answer:

y = 91/33

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

Step-by-step explanation:

<u>Step 1: Define</u>

26 - (6y - 10) = 27y - 18 - 37

<u>Step 2: Solve for </u><u><em>y</em></u>

  1. Distribute negative:                    26 - 6y + 10 = 27y - 18 - 37
  2. Combine like terms:                    -6y + 36 = 27y - 55
  3. Add 6y to both sides:                 36 = 33y - 55
  4. Add 55 to both sides:                 91 = 33y
  5. Divide 33 on both sides:             91/33 = y
  6. Rewrite:                                        y = 91/33
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Nadya [2.5K]
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3 0
4 years ago
Y=x+4 y=-2x-2 explain the awnser plz
Sliva [168]

Answer:

x = -2 and y = 2

Step-by-step explanation:

We have the following system of linear equations;

y=x+4

y=-2x-2

To solve the above system, we shall be equating the right hand sides of the two equations since we have y's on the left hand side of both equations;

x + 4 = -2x - 2

add 2x on both sides of the equation;

x + 4 + 2x = -2x - 2 + 2x

3x + 4 = -2

subtract 4 on both sides of the equation;

3x + 4 - 4 = -2 - 4

3x = -6

x = -2

We can use the first equation y=x+4 to determine the value of y;

y = -2 + 4

y = 2

The solution to the system of linear equations is thus;

x = -2 and y = 2

6 0
3 years ago
3x - 4y = -15 ; 4x +3y =5
Kipish [7]
Using elimination method to find y
3x - 4y = -15  (multiply 4)
4x + 3y = 5    (multiply 3)
------------------------------------
12x - 16y = -60
12x + 9y  = 15
--------------------- - (substract)
         -25y = -75
               y = 3

Using subtitution method to find x
3x - 4y = -15
3x - 4(3) = -15
3x - 12 = -15
3x = -3
x = -1

The solution (-1,3)
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3 years ago
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Snezhnost [94]

Answer:18

Step-by-step explanation:

8 0
3 years ago
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castortr0y [4]

Answer:

\huge\mathcal\red{here's \:  your \:  solution..} \\  \\  \cos = base \div hypotenuse \:  \\  \\  \cos(60)  = 1 \div 2 \\  \\  \cos = a \div 14 \\  \\ a \div 14 = 1 \div 2 \\  \\ a = 14 \div2 \\  \\ a = 7 \: cm \\  \\ \huge\mathfrak\green{hope \: it \: helps..}

4 0
3 years ago
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