Answer:
And the explanation of this number is:"The number of text messages for Kendra it's 2.26 deviations above the mean"
Step-by-step explanation:
1) Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
2) Calculate the z score
Let X the random variable that represent the number of text messages per month, and for this case we know the distribution for X is given by:
Where 
and 
And the best way to solve this problem is using the normal standard distribution and the z score given by:
If we apply this formula to our probability we got this:
And the explanation of this number is:"The number of text messages for Kendra it's 2.26 deviations above the mean"
Answer:
75+ po e photo math nyo po sa play store I download nyo po
Step-by-step explanation:
sana po makatulong po
You would end up having $12,000 at that rate since 54 divided by 9 is 6
Answer:
227 ft^2
Step-by-step explanation:
Here, we are tasked with calculating the roaming area that Fido has
Calculating this is same as calculating the area of circle that has a radius which is equal to the length of the leash
Mathematically, the area would be
A = π * r^2
A = 3.14 * 8.5^2
A = 226.865 ft^2
To the nearest square foot, this is 227 ft^2
- Rounding 789 nearest to tens will be 790.
Step-step Explanation:
Let's know how to round any number nearest to tens (Rules):-
We know tens place in any no. from left is at second place and number right to tens place need to be changed as:-
- If last digit is 0, then we don't have to do any rounding, because it is already to the ten.
- We round the no. down to the nearest ten if the last digit in the no. is 1, 2, 3, or 4
- We round the no. up to the nearest ten if the last digit in the no. is 5, 6, 7, 8, or 9.
