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iris [78.8K]
3 years ago
6

If Speed=80Km/h and Time=2hr then Find distance in Km?

Mathematics
1 answer:
Ksju [112]3 years ago
4 0

Answer:

Distance = 160km

Step-by-step explanation:

According to the Question ,

  • Speed = 80km/hr
  • Time = 2hr
  • Distance = ?

We know the formula of speed as ,

\implies Speed \times Time = Distance \\\\\implies Distance = 80km/hr \times 2hr \\\\\implies \boxed{\boxed{ Distance = 160\ km}}

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Evaluate h(5t^{2})given that h(t)=17-11t
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4 years ago
In college​ basketball, a shot made from beyond a designated arc radiating about 20 ft from the basket is worth three points ins
denis-greek [22]

Answer:

a) By the Central Limit Theorem, the distribution would be approximately normal, with mean \mu = 0.45 and standard deviation s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.45*0.55}{100}} = 0.0497

b) 4.02 standard deviations below the mean.

c) Making 25 or less shots has a pvalue of -4.02. Z-scores lower than -2 are considered surprising, so yes, it would be surprising for him to make only 25 of these shots.

Step-by-step explanation:

To solve this question, we are going to need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For proportions, we have that the mean is \mu = p and the standard deviation is s = \sqrt{\frac{p(1-p)}{n}}

In this problem, we have that:

p = 0.45, n = 100

a)By the Central Limit Theorem, the distribution would be approximately normal, with mean \mu = 0.45 and standard deviation s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.45*0.55}{100}} = 0.0497

b)This is Z when X = 0.25.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{0.25 – 0.45}{0.0497}

Z = -4.02

4.02 standard deviations below the mean.

c) Making 25 or less shots has a pvalue of -4.02. Z-scores lower than -2 are considered

surprising, so yes, it would be surprising for him to make only 25 of these shots.

3 0
3 years ago
Find S11 for 1 + 2 + 4 + 8 +
Free_Kalibri [48]
Evaluating the given sequence, it is evident that the next number is twice the number prior to it. Thus, the given is a geometric sequence with first term (a1) equal to 1 and common ratio of 2. The geometric series may be calculated by the equation,
 
                                            Sn = a1 x (1 - r^n) / (1 - r)

where Sn is the sum of n terms in this case, n = 11. 
Substituting the known values, 
 
<span>                                      Sn = 1 x (1 - 2^11) / (1 - 2) = 2047
</span>
Thus, S11 is 2047. 
4 0
4 years ago
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