What is the measure of the following angle?AOD
2 answers:
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Answer:
Step-by-step explanation:
1. Make sure all your denominators are the same, you can do this by multiplying them all by 3 or 7, 2 and 1/3 would become 2 7/21, 3/7 would become 9/21, 2 and 1/3, would become 2 and 7/21, and so on and so forth, leaving us with
2+
/ 2
* 1
2. Now, I would go and solve each side of the equation because we divide them, we can add 2 and
together to get 2
, because 7 + 9 = 16
2 / 2
* 1
3. We can do the same thing to the other side, by multiplying the two of them. I'm going to convert both of them to just fractions, 2 becomes
and 1
becomes
*
Now we can reduce them, and for our first fraction divide the top and bottom by 7, giving us and the second one by 3, which gives us
*
now we cross divide, where we replace the 7's with ones because they're right across from each other to get
and
, or just 10.
* 10 =
4. So now we can do a similar thing with the first half of our equation and convert it into a fraction and not a mixed number.
/
Now we multiply divide them, and the easiest way I learned how to do this was by keep the first fraction in its place, and flipping the denominator and numerator of the second, and multiplying them.
so *
which if we multiply both sides, you get
I'll save you some times and simplify it for you, the greatest common factor is 6 so we divide the top and bottom by 6 to get
See the picture attached to better understand the problem
we know that
A quadrilateral is called Cyclic quadrilateral <span>if its all vertices lie on the circle.
</span><span>The opposite angles of a Cyclic - quadrilateral are supplementary
</span>so
∠A+∠C=180°
and
∠B+∠D=180°
therefore
the answer is
<span>C) The sum measure of ∠B and ∠D equals 180°</span>
we know that
A quadrilateral is called Cyclic quadrilateral <span>if its all vertices lie on the circle.
</span><span>The opposite angles of a Cyclic - quadrilateral are supplementary
</span>so
∠A+∠C=180°
and
∠B+∠D=180°
therefore
the answer is
<span>C) The sum measure of ∠B and ∠D equals 180°</span>