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Mama L [17]
2 years ago
13

Drag the items to complete the sentences about the end behavior of the exponential function graphed.

Mathematics
1 answer:
zalisa [80]2 years ago
5 0

Answer:

as x --> oo, f(x) = oo (infinite)

as x -- -oo, f(x) = 3

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An online music club sells compact discs for $13.95 each plus $1.95 shipping and handling per order. If Maria's total bill was $
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The equation is 13.95x+1.95=85.65
The answer is 6 compact discs.
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A married couple had a combined annual income of 63,000. The wife made 7,000 more than her husband. What was each of their incom
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A ferry will safely accommodate 82 tons of passenger cars. Assume that the meanweight of a passenger car is 2 tons with standard
Shalnov [3]

Answer:

The probability that the maximum safe-weight will be exceeded is <u>0.0455 or 4.55%</u>.

Step-by-step explanation:

Given:

Maximum safe-weight of 37 cars = 82 tons

∴ Maximum safe-weight of 1 car (x) = 82 ÷ 37 = 2.22 tons (Unitary method)

Mean weight of 1 car (μ) = 2 tons

Standard deviation of 37 cars = 0.8 tons

So, standard deviation of 1 car is given as:

\sigma=\frac{0.8}{\sqrt{37}}=0.13

Probability that maximum safe-weight is exceeded, P(x > 2.22) = ?

The sample is normally distributed (Assume)

Now, let us determine the z-score of the mean weight.

The z-score is given as:

z=\frac{x-\mu}{\sigma}\\\\z=\frac{2.22-2}{0.13}\\\\z=\frac{0.22}{0.13}=1.69

Now, finding P(x > 2.22) is same as finding P(z > 1.69).

From the z-score table of normal distribution curve, the value of area under the curve for z < 1.69 is 0.9545.

But we need the area under the curve for z > 1.69.

So, we subtract from the total area. Total area is 1 or 100%.

So, P(z > 1.69) = 1 - P(z < 1.69)

P(z>1.69)=1-0.9545=0.0455\ or\ 4.55\%

Therefore, the probability that the maximum safe-weight will be exceeded is 0.0455 or 4.55%.

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3 years ago
Identify the DELETION mutation from the following DNA sequence:ATG CCA AAT
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Answer

Hello, There!

:Identify the DELETION mutation from the following DNA sequence

ATG CCA AAT.

Hope this helps!

4 0
3 years ago
The area of a triangle is 80x^5y^3. The height of the triangle is x^4y. What is the length of the base of the triangle?
svetoff [14.1K]
Area of a triangle is given by 1/2bh where b is the base and h is the perpendicular height of the triangle.
The area is 80x∧5y³ and the height is x∧4y
Thus; 80x∧5y³ = 1/2(x∧4y) b
         160x∧5y³ = (x∧4y)b
                  b = (160x∧5y³)/ x∧4y)
                  b = 160xy²
Therefore, the base of the triangle is 160xy²
7 0
2 years ago
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