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olga nikolaevna [1]
3 years ago
5

Please help!?

Mathematics
1 answer:
Alex787 [66]3 years ago
5 0

Answer:

x=63.25

Step-by-step explanation:

Hi there!

We're given ΔDEF with m<E=90°, m<D=49°, DE=55, and EF=x

we need to find the value of x

Let's use trigonometry to do it

Since we are given the measures of the 2 legs (the sides that make up the 90° angle), let's use tangent, specifically tan(49), since we are given the measure of that angle

Recall that tangent is \frac{opposite}{adjacent}

in reference to m<D (the angle that is 49°), the opposite side is EF (x) and the adjacent side is DE (55)

so tan(49)=\frac{x}{55}

plug tan(49) into your calculator; remember to have the calculator on degree mode

tan(49)≈1.15 (rounded to the nearest hundredth)

so that means:

1.15=\frac{x}{55}

multiply both sides by 55 to clear the fraction

63.25=x

Hope this helps!

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Answer:

Option (3)

Step-by-step explanation:

From the picture attached,

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Total students who took the exam = 17 + 14 + 5 + 9 = 45

Option (1)

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Fraction of students who earned C = \frac{\text{Students who earned C}}{\text{Total students}}

                                                          = \frac{5}{45}

                                                          = \frac{1}{9}

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Option (2)

"3% more students earned an A then B"

Percentage of students who earned A = \frac{\text{Students got A}}{\text{Total students who took the exam}}\times 100

                                                                = \frac{17}{45}\times 100

                                                                = 37.78%

Percentage of students who earned B = \frac{\text{Students got B}}{\text{Total students who took the exam}}\times 100

                                                                = \frac{14}{45}\times 100

                                                                = 31.11%

Difference in percentage = 37.78 - 31.11

                                          = 6.67%

Therefore, this option is not correct.

Option (3)

"20% of the students earned a D"

Percentage of students who earned D = \frac{\text{Students got D}}{\text{Total students who took the exam}}\times 100

                                                                 = \frac{9}{45}\times 100

                                                                 = 20%

Option (3) is the correct option.

Option (4)

" \frac{1}{4} of the class earned a B"

Fraction of class who earned B = \frac{\text{Students got B}}{\text{Total students who took the exam}}

                                                    = \frac{14}{45}

Therefore, Option (4) is not correct.                                        

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