Answer:
<h2>46•18</h2>
Step-by-step explanation:
<h3> I=PRT/100</h3><h2> 6740×<u>1</u><u>0</u>×7</h2><h2> 100</h2><h2> 674×1×7</h2><h2> 4618</h2><h2>the nearest hundredth is a 46•18 this is my answer</h2>
-x+y=3
y=x+3
2x + x + 3 =6
3x + 3 = 6
3x = 3
x = 1
-1 + y = 3
y = 4
2(1) + y = 6
2 + y = 6
y = 4
Solution: (1, 4)
Answer:
A(t)= 18000(0.988)^t
Step-by-step explanation:
Given data
Ryan bought a brand new car for $18,000
Its value depreciated at a rate of 1.2%
Let us use the compound expression
A= P(1-r)^t
substitute
A= 18000(1-0.012)^t
A(t)= 18000(0.988)^t
Hence the expression is A(t)= 18000(0.988)^t
700 x .03 x 20 = 420
420 + 700
1120 is in the account after 20 years
A.A’(5,-5),B’(1,-5),C’(1,-2)