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lesantik [10]
3 years ago
14

An automobile manufacturer sold 30,000 new cars, one to each of 30,000 customers, in a certain year. The manufacturer was intere

sted in investigating the proportion of the new cars that experienced a mechanical problem within the first 5,000 miles driven. (a)
A list of the names and addresses of all customers who bought the new cars is available. Describe a sampling plan that could be used to obtain a simple random sample of 1,000 customers from the list.

Each customer from a simple random sample of 1,000 customers who bought one of the new cars was asked whether they experienced any mechanical problems within the first 5,000 miles driven. Forty customers from the sample reported a problem. Of the 40 customers who reported a problem, 13 customers, or 32.5%, reported a problem specifically with the power door locks. (b)

Explain why 0.325 should not be used to estimate the population proportion of the 30,000 new cars sold that experienced a problem with the power door locks within the first 5,000 miles driven. (c)

Based on the results of the sample, give a point estimate of the number of new cars sold that experienced a problem with the power door locks within the first 5,000 miles driven.
Mathematics
1 answer:
snow_lady [41]3 years ago
4 0
A) In order to create a sampling plan, you need to follow the following 5 steps:
    1) Define the sample population: who are the customers you want to contact?
       The costumers who bought a new car on a certain year.
    2) Define the size of population: how many customers are you going to contact?
       Of the 30000 customers who bought a car, you want to contact 1000 customers.
    3) Define the contact options: how are you going to contact the customers?
       You have a list of names and addresses, therefore you can send a questionnaire via mail.
    4) Form a sampling frame: what is the time or contact frame to get in touch with your customers? 
       You will send the questionnaires and you will wait two months for the answer.
    5) Define the analysis method: is yours a qualitative or quantitative research?
     In your case, you want a quantitative research and therefore a probabilistic sampling.

B) The 32.5% probability refers to customers having issues with the power doors locks among the costumers who had problems, it does not consider the customers who did not have any problem or those who had problems after the first 5000 miles.

C) In order to find the probability of a power door lock problem if there have been problems within the first 5000 miles, we need to consider the whole sample:
P = 13 / 1000
   = 0.013

Therefore, 
N = <span>0.013 </span>× 30000
   = 390

Hence, the number of new cars sold that experienced a problem with the power door locks within the first 5000 miles will be 390.
         
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(8v3-80v2+6)\(v-10)
Leto [7]

\frac{(8v^3-80v^2+6)}{v-10}

Use long division for dividing

(8v^3-80v^2+6) Here 'v' term is missing so we use 0vW

Divide (8v^3-80v^2+0v+6) by v-10 using long division

Step 1: Put 8v^2 at the top

step 2: multiply 8v^2 with v-10  and put it at the bottom

step 3: subtract it

We will get remainder 6

so quotient is  8v^2

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8 0
4 years ago
A poker hand consisting of 9 cards is dealt from a standard deck of 52 cards. Find the probability that the hand contains exactl
Andrew [12]

Answer: \dfrac{^{12}C_{6}\times^{40}C_3}{^{52}C_9} or  \dfrac{228}{91885} .

Step-by-step explanation:

Given : A poker hand consisting of 9 cards is dealt from a standard deck of 52 cards.

The total number of cards in a deck 52

Number of faces cards in a deck = 12

Number of cards not face cards = 40

The total number of combinations of drawing 9 cards out of 52 cards = ^{52}C_9

Now , the combination of 9 cards such that exactly 6 of them are  face cards =  ^{12}C_{6}\times^{40}C_3

Now , the probability that the hand contains exactly 6 face cards will be :-

\dfrac{^{12}C_{6}\times^{40}C_3}{^{52}C_9}

=\dfrac{\dfrac{12!}{6!6!}\times\dfrac{40!}{3!37!}}{\dfrac{52!}{9!\times43!}}\ \ [\because\ ^nC_r=\dfrac{n!}{r!(n-r)!}]\\\\=\dfrac{228}{91885}

Hence, the probability that the hand contains exactly 6 face cards. is  \dfrac{228}{91885} .

6 0
3 years ago
(x3 + 9x2 + 1)(3x2 + 4x − 4)
kap26 [50]
I don’t understand the question so I answer in two ways

4 0
3 years ago
A civil engineer is analyzing the compressive strength of concrete. Compressive strength is normally distributed with A random s
wel

Answer:

95%: (3278.354 ; 3270.083)

99% : (3221.646 ; 3278.354)

Step-by-step explanation:

Given :

Sample size, n = 12

Mean, xbar = 3250

Sample standard deviation = √1000

The 95% confidence interval :

Mean ± Margin of error

Margin of Error = Tcritical * s/√n

Tcritical at 0.05, df=12-1 = 11 ;

Tcritical at 95% = 2.20

Hence,

Margin of Error = (2.20 * √1000/√12) = 20.083

Confidence interval : 3250 ± 20.083

Lower boundary = 3250 - 20.083 = 3229.917

Upper boundary = 3250 + 20.083 = 3270.083

2.)

The 99% confidence interval :

Mean ± Margin of error

Margin of Error = Tcritical * s/√n

Tcritical at 0.01, df=12-1 = 11 ;

Tcritical at 99% = 3.106

Hence,

Margin of Error = (3.106 * √1000/√12) = 28.354

Confidence interval : 3250 ± 28.354

Lower boundary = 3250 - 28.354 = 3221.646

Upper boundary = 3250 + 28.354 = 3278.354

3 0
3 years ago
Sweatshirt = $32 t-shirts = $14 ,
rodikova [14]
Cost of a sweatshirt = $32
Then
Cost of 14 sweatshirts = (32 * 14) dollars
                                     = 448 dollars
Cost of a t-shirt = $14
Cost of 32 t-shirts = (32 * 14) dollars
                               = 448 dollars
So it can seen from the deduction that the cost of 14 sweatshirts and 32 t-shirts comes out to be same and equal to $448. I hope the answer and the procedure of doing this problem is clear to you. It is important to look at all the details given in the question and then start solving the problem.
4 0
3 years ago
Read 2 more answers
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