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Komok [63]
3 years ago
9

Write an explicit formula for the recursive formula A(n) = A(n - 1) + 3; A(1) = 6

Mathematics
1 answer:
arsen [322]3 years ago
7 0

Answer:

a_{n} = 3n + 3

Step-by-step explanation:

The sequence is arithmetic with explicit formula

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

From the recursive formula

a₁ = 6 and d = 3 [ the constant being added to A(n - 1) ] , then

a_{n} = 6 + 3(n - 1) = 6 + 3n - 3 = 3n + 3

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Express (x+4)2as an equivalent trinomial. Test the equivalency using x = 1.
Crazy boy [7]

Answer:

\boxed {\boxed {\sf x^2+8x+16}}

Step-by-step explanation:

<h3>1. Express as an Equivalent Trinomial</h3>

To multiply two binomials (expressions with 2 terms), we can use the FOIL (first, outside, inside, last) method.

We are given this expression:

(x+4)^2

The expression (x+4) is being squared, which is equal to multiplying the term by itself twice.

(x+4)(x+4)

Next, multiply the first terms from both binomials, then repeat for the outside, inside, and last terms.

  • First: x*x= x²
  • Outside: x*4= 4x
  • Inside: 4 *x= 4x
  • Last: 4*4= 16

Put the products into one expression.

x^2+4x+4x+16

Combine like terms. 4x and 4x both have the variable x, so they can be combined.

x^2+(4x+4x)+16

x^2+8x+16

<h3>2. Test using x=1</h3>

Next, substitute 1 in for x in both the original expression and the trinomial we found. If they are equivalent, the results will be the same.

1. (x+4)²

(1+4)²

(5)² = <u>25</u> \checkmark

2. x²+8x+16

(1)²+8(1)+16

1+8(1)+16

1+8+16

9+16= <u>25 </u>\checkmark<u />

<u />

If x=1, both the original binomial and trinomial equal 25, so we know they are equivalent.

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Construct a Tangent Line
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D,A,C,E,B

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